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3241004551 [841]
3 years ago
5

How many real number solutions does this have 3x^2 + 8x +7=0

Mathematics
1 answer:
kompoz [17]3 years ago
5 0

Answer:

  zero

Step-by-step explanation:

The answer to that question is best found by looking at the value of the <em>discriminant</em>.

For quadratic ax^2 +bx +c = 0, the value of the discriminant is ...

  d = b^2 -4ac

Here, you have a=3, b=8, c=7, so the discriminant is ...

  d = 8^2 -4(3)(7) = 64 -84 = -20

When the discriminant is negative, both solutions are complex (not real).

There are zero real solutions to this equation.

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Mama L [17]

Multiplying both sides by y^2 gives

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so that substituting v=y^3 and hence \frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx} gives the linear ODE,

\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1

Now multiply both sides by 3x^2 to get

x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2

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\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}

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3 years ago
A map is drawn using a scale of 1 cm/80 mi. Two cities are 280miles apart. How far apart are the cities on the map
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4 years ago
Which steps should be used to graph the equation below? y-4=1/3(x+2)
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       [] The finished graph is attached

       [] I have also graphed the original equation to show that they overlap, showing that our simplification works

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

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6 * 6 * 6 * 6 = 36*36=1296

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3 years ago
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