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Alisiya [41]
3 years ago
6

Allowance for Doubtful Accounts has a credit balance of $500 at the end of the year (before adjustment), and bad debt expense is

estimated at 3% of credit sales. If credit sales are $300,000, the amount of the adjusting entry to record the estimated uncollectible accounts receivable is
Business
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer:

Adjusting entry to record the estimated uncollectible accounts receivable is:

Debit Bad debt expense                                  $8,500

Credi Allowance for doubtful accounts          $8,500

<em>(To record bad debt expense for the year)</em>

Explanation:

The company uses percentage of credit sale to arrive at an estimated amount of accounts receivable that is deemed irrecoverable.

3% of credit sales of $300,000 = $9,000

Since there is an existing credit balance of $500 in the allowance for doubtful accounts, in order to reinstate the balance in that account to $9,000, we need to remove the existing balance from the calculated estimate. Therefore, $9,000 - $500 = $8,500 becomes the necessary adjustment to Bad debt expense.

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Sally’s parents deposited $15,000 into a college savings account on her third birthday. The account had an interest rate of 9.6%
kozerog [31]

Answer:

The correct option is yes,the $15,000 will double each 7.5 years.In 15 years ,it will double twice.

Explanation:

The 72 rule stipulates that the number of years it would take an investment to achieve accumulate a certain amount- future value, can be computed by dividing 72 by the interest rate earns by the investment

N, the number of years=72/9.6

                                      =7.5 years

Invariably,in 7.5 years' when Sally would have been 10.5 years(3 years now+7.5 years) the investment would have doubled.

By another 7.5 years when Sally would have been 18 years(10.5 years +7.5 years), the investment would have doubled twice.

The 72 rule is fast-track approach to calculating the duration of an investment.

7 0
3 years ago
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Audio engineers at 3XT2 have determined that an anechoic additive will increase isolation and improve signal to noise by about 2
Crazy boy [7]

Answer:

The correct answer is $83230

Explanation:

Solution

Given that:

The Present worth of geometric series is shown below

= A *[1 - (1+g)^n /(1+i)^n] / (i-g)

Now,

The present  cost of worth from EOY 5 to EOY 13 at EOY 4 = 7000 *[1 - (1+0.12)^9 /(1+0.15)^9] / (0.15-0.12)

Thus,

= 7000 *[1 - (1.12)^9 /(1.15)^9] / (0.03)

Which is,

= 7000 * 7.0572647

= 49400.85

Now, The NPW of all costs = 35000 + 7000*(P/A,15%,4) + 49400.85*(P/F,15%,4)

= 35000 + 7000*2.854978 + 49400.85*0.571753

= 83229.93

Therefore the sound improvement better result in a net present worth profit of how much to negate the costs is $83229.93 or 83230

Note: EOY = End of year.

6 0
3 years ago
While _______ decisions will generally need to be processed via the ______ system in our brains in order for us to reach a good
Jet001 [13]

Answer:

Nonprogrammed; reflective; programmed; reactive

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Programmed decisions can be regarded as decision which involves well understood criteria when making it,. nonprogrammed decisions on the other hand can be explained as decisions which are novel, they are decision that does not have clear guidelines when trying to reach solution. rules as well as guidelines can be set up for programmed decisions by Managers when known fact is available because this will enhance in reaching

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5 0
3 years ago
Ramapo Company produces two products, Blinks and Dinks. They are manufactured in two departments, Fabrication and Assembly. Data
ehidna [41]

Answer:

a.$7.43 per machine hour

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The computation of the single plant wide rate is shown below:

Single plant wide rate = Total overhead cost ÷ Machine hours

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Total overhead cost = $84,000 + $72,000 = $156,000

And, the machine hours is

= 1,000 units × 5 + 2,000 units × 8

= 5,000 + 16,000

= 21,000 machine hours

So, the single plant wide rate is

= $156,000 ÷ 21,000 machine hours

= $7.43 per machine hour

4 0
4 years ago
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