Answer:
In the image attached you can find the Unit 7 homework.
We need to findt he missing measures of each figure.
<h3>1.</h3>
Notice that the first figure is a rectangle, which means opposite sides are congruent so,
VY = 19
WX = 19
YX = 31
VW = 31
To find the diagonals we need to use Pythagorean's Theorem, where the diagonals are hypothenuses.
![VX^{2}=19^{2}+31^{2}\\ VX=\sqrt{361+961}=\sqrt{1322} \\VX \approx 36.36](https://tex.z-dn.net/?f=VX%5E%7B2%7D%3D19%5E%7B2%7D%2B31%5E%7B2%7D%5C%5C%20VX%3D%5Csqrt%7B361%2B961%7D%3D%5Csqrt%7B1322%7D%20%20%5C%5CVX%20%5Capprox%2036.36)
Also,
, beacuse rectangles have congruent diagonals, which intercect equally.
That means, ![ZX = \frac{VX}{2} \approx \frac{36.36}{2}\approx 18.18](https://tex.z-dn.net/?f=ZX%20%3D%20%5Cfrac%7BVX%7D%7B2%7D%20%5Capprox%20%5Cfrac%7B36.36%7D%7B2%7D%5Capprox%2018.18)
<h3>2.</h3>
Figure number two is also a rectangle.
If GH = 14, that means diagonal GE = 28, because diagonals intersect in equal parts.
Now, GF = 11, because rectangles have opposite sides congruent.
DF = 28, because in a reactangle, diagonals are congruent.
HF = 14, because its half of a diagonal.
To find side DG, we need to use Pythagorean's Theorem, where GE is hypothenuse
![GE ^{2}=11^{2}+DG^{2}\\28^{2}-11^{2}=DG^{2}\\DG=\sqrt{784-121}=\sqrt{663}\\ DG \approx 25.75](https://tex.z-dn.net/?f=GE%20%5E%7B2%7D%3D11%5E%7B2%7D%2BDG%5E%7B2%7D%5C%5C28%5E%7B2%7D-11%5E%7B2%7D%3DDG%5E%7B2%7D%5C%5CDG%3D%5Csqrt%7B784-121%7D%3D%5Csqrt%7B663%7D%5C%5C%20%20DG%20%5Capprox%2025.75)
<h3>3.</h3>
This figure is also a rectangle, which means all four interior angles are right, that is, equal to 90°, which means angle 11 and the 59° angle are complementary, so
![\angle 11 +59\°=90\°\\\angle 11=90\°-59\°\\\angle 11=31\°](https://tex.z-dn.net/?f=%5Cangle%2011%20%2B59%5C%C2%B0%3D90%5C%C2%B0%5C%5C%5Cangle%2011%3D90%5C%C2%B0-59%5C%C2%B0%5C%5C%5Cangle%2011%3D31%5C%C2%B0)
Now, angles 11 and 4 are alternate interior angles which are congruent, because a rectangle has opposite congruent and parallel sides.
![\angle 4 = 31\°](https://tex.z-dn.net/?f=%5Cangle%204%20%20%3D%2031%5C%C2%B0)
Which means
, beacuse it's the complement for angle 4.
Now,
, because it's a base angle of a isosceles triangle. Remember that in a rectangle, diagonals are congruent, and they intersect equally, which creates isosceles triangles.
, by interior angles theorem.
, by vertical angles theorem.
, by supplementary angles.
, by vertical angles theorem.
, by complementary angles.
, by alternate interior angles.
, by complementary angles.
<h3>4.</h3>
, because it's one of the four interior angles of a rectangle, which by deifnition are equal to 90°.
, by alternate interior angles and by given.
, by complementary angles.
, by complementary angles.
, by interior angles theorem.
, by supplementary angles.
<h3>5.</h3>
, by supplementary angles.
, by interior angles theorem, and by isosceles triangle theorem.
, by definition of rectangle.
, by interior angles theorem, and by isosceles triangle theorem.
, by complementary angles.
, by alternate interior angles.
<h3>6.</h3>
The figure is a rectangle, which means its opposite sides are equal, so
![WZ=XY\\7x-6=3x+14\\7x-3x=14+6\\4x=20\\x=\frac{20}{4}\\ x=5](https://tex.z-dn.net/?f=WZ%3DXY%5C%5C7x-6%3D3x%2B14%5C%5C7x-3x%3D14%2B6%5C%5C4x%3D20%5C%5Cx%3D%5Cfrac%7B20%7D%7B4%7D%5C%5C%20x%3D5)
Then, we replace this value in the expression of side WZ
![WZ=7x-6=7(5)-6=35-6=29](https://tex.z-dn.net/?f=WZ%3D7x-6%3D7%285%29-6%3D35-6%3D29)
Therefore, side WZ is 29 units long.
<h3>7.</h3>
We know that the diagonals of a rectangle are congruent, so
![SQ=PR\\11x-26=5x+28\\11x-5x=28+26\\6x=54\\x=\frac{54}{6}\\ x=9](https://tex.z-dn.net/?f=SQ%3DPR%5C%5C11x-26%3D5x%2B28%5C%5C11x-5x%3D28%2B26%5C%5C6x%3D54%5C%5Cx%3D%5Cfrac%7B54%7D%7B6%7D%5C%5C%20x%3D9)
Then,
![PR=5x+28=5(9)+28=45+28=73](https://tex.z-dn.net/?f=PR%3D5x%2B28%3D5%289%29%2B28%3D45%2B28%3D73)
Therefore, side PR is 73 units long.