By using the information you have, you can use make a proportion to solve this.
You burn 4 logs in 2 hours or 4/2. You are comparing this to your unknown number, x, over 8 hours. So it looks like this 4/2 = x/8. You read it as four logs in two hours is x logs in eight hours. To solve you cross multiply. You do 2 times x and 4 times eight. That would be 2x= 32. Your goal is getting x alone, so divide each side by 2. Your answer is x= 16 logs in eight hours. You can solve this different and maybe easier ways but this is the best way if you want to get used to going this in algebra. Hope that helps! :)
Answer:
70 + 4D
Step-by-step explanation:
- (2 x 100) + (7 x 10) + (4 x D) + (2 x 100)
- (200) + (70) + 4D + 200
-200 + 70 +4D + 200
-130 + 4D + 200
70 + 4D
All you do is measure it with a ruler and for every 1 cm you get multiply it by 8.5ft.
so for example if you got 6cm then you would multiply it by 8.5ft and your answer would be 51ft.
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
