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Mkey [24]
3 years ago
15

Help meee please.........

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer: B

x looks like .9 so if -.9 + 3 = -2.1 then you can see that's the answer on the number line, hope it helps, I'm 80% sure it's right

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Complete the following statement. A fraction in lowest terms is in its __________________________________
pantera1 [17]

Answer:

Reduced form

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
Find the equation of a line with each of the following characteristics. a) parallel to the line y = 3x + 5 and has a y-intercept
Vedmedyk [2.9K]

Answer:

y = 1/2x - 1

Step-by-step explanation:

When you put all three equations from the question into a graph and then input the equation i just gave you it will be perpendicular to line B & C, also it will be parallel to line A. Finally you can check yourself that it also has a y-intercept of (0,-1) & an x-intercept of (2,0). Hopefully this helps out & gets brainliest. xD

4 0
3 years ago
If f(x)=4x^2+1 and g(x)=x^2-5 find(f+g)(x)
Zepler [3.9K]

Answer:

\large\boxed{(f+g)(x)=5x^2+6}

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\f(x)=4x^2+1,\ g(x)=x^2-5\\\\\text{Substitute:}\\\\(f+g)(x)=(4x^2+1)+(x^2-5)\\\\=4x^2+1+x^2-5\qquad\text{combine like terms}\\\\=(4x^2+x^2)+(1+5)\\\\=5x^2+6

6 0
3 years ago
What is the value of discontinuity of x^2+8x+4/x^2-x-6? Choices:
Morgarella [4.7K]

Answer:

-2

Step-by-step explanation:

Hello,

First of all, let's check the denominator.

x^2-x-6 \ \ \text{ *** How to factorise it ...? ***}\\\\\text{*** The product of the roots is -6=-2*3 and their sum is 1 ***}\\\\x^2-x-6=x^2-3x+2x-6=x(x-3)+2(x-3)=(x+2)(x-3)

Now, let's see the numerator.

x^2+8x+4 \ \text{ *** -2 is not a zero as ***}\\\\(-2)^2+8*(-2)+4=4-16+8=-4\\\\\text{*** 3 is not a zero as ***}\\\\3^2+8*3+4=9+24+4=37\\

So we cannot factorise the numerator with (x+2) or (x-3)

Then, -2 and 3 are the the discontinuities of the expression.

There is only -2 in the list, this is the correct answer.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
What are the solutions of the system?
miskamm [114]
We have the following system of equations:
 y = -6x-6
 y = x2-5x-6
 Matching we have:
 x2-5x-6 = -6x-6
 Rewriting we have:
 x2-5x-6 + 6x + 6 = 0
 x2 + x = 0
 Rewriting:
 x (x + 1) = 0
 The solutions are:
 x = 0
 x = -1
 For x = 0
 y = -6 (0) -6 = 0-6 = -6
 y = -6
 For x = -1
 y = -6 (-1) -6 = 6-6 = 0
 y = 0
 The solutions are:
 (x, y) = (0, -6)
 (x, y) = (- 1, 0)
 Answer:
 
The solutions of the system are:
 (-1, 0) and (0, -6)
3 0
3 years ago
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