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Zarrin [17]
3 years ago
10

The temperature at 9am was 4 degrees Celsius. At 7pm the temperature was

Mathematics
1 answer:
madam [21]3 years ago
4 0

Answer:

i'm not sure

Step-by-step explanation:

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Anna71 [15]

Answer:

11. the first one 12. the last one

Step-by-step explanation:

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3 years ago
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The germination rate is the rate at which plants begin to grow after the seed is planted.
chubhunter [2.5K]

Answer:

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

\hat p=\frac{7}{15}=0.467 estimated proportion of seeds germinated

p_o=0.9 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:  

Null hypothesis:p\geq 0.9  

Alternative hypothesis:p < 0.9  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

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3 years ago
Uh i need help asap lol..
ahrayia [7]
54 degrees because the angles are equal
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Elza [17]

I believe its b because theres a large range of scores

7 0
3 years ago
Write the equation of a line that passes through point (2,3) and (0,9).
11Alexandr11 [23.1K]

Slope-intercept form:

y = mx + b        

"m" is the slope, "b" is the y-intercept (the y value when x = 0) or (0,y)


To find "m", you can use the slope formula and plug in the two points:

(2,3) = (x₁ , y₁)

(0,9) = (x₂ , y₂)


m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{9-3}{0-2}

m=\frac{6}{-2}

m = -3


y = -3x + b

To find "b", you can plug in one of the points into the equation (however they already gave you the y-intercept (0,9) or 9)


(2,3)

y = -3x + b

3 = -3(2) + b

3 = -6 + b

9 = b


y = -3x + 9


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3 years ago
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