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fredd [130]
3 years ago
10

Graph the equation by plotting three points. If all three are correct, the line will appear. 2y = 5x + 11

Mathematics
1 answer:
slega [8]3 years ago
4 0

Pick the following

x = 0 in which case

2y = 11    and

y = 11/2

y = 5.5

============

x = 1

2y = 5x + 11

2y = 5*1 + 11

2y = 5 + 11

2y = 16

y = 8.    

==========

x = - 2 and x = - 10 are done the same way.

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Find point G on AB such that the ratio of AG to GB is 3:2
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The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)

How to partition a Line segment?

The formula to partition a line segment in the ratio a:b is;

(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]

We want to find point G on AB such that the ratio of AG to GB is 3:2.

From the graph, the coordinates of the points A and B are;

A(3, 5) and B(5, 0)

Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;

G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]

G(x, y) = (21/5, 10/5)

G(x, y) = (4.2, 2)

Read more about Line segment partition at; brainly.com/question/17374569

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8 0
2 years ago
Find the missing number of each unit rate. 18/3= ?/1 and 12/2= ?/1
gtnhenbr [62]

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3 0
3 years ago
Paul and jose are trying to measure the height of a tree. paul is standing 19m from the foot of the tree and measures the angle
Nina [5.8K]
The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as x.
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
cos(59)= \frac{19}{h}
h= \frac{19}{cos(59)}
h=36.9
Now we can use the law of sines to find the distance x between Paul and Jose:
\frac{sin(43)}{36.9} = \frac{sin(16)}{x}
x= \frac{36.9sin(16)}{sin(43)}
x=14.9

Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
19m+14.9=33.9m

We can conclude that Jose is 33.9m from the base of the tree.

3 0
3 years ago
Help me with these math questions....
Nady [450]

Answer: cotθ

<u>Step-by-step explanation:</u>

 tanθ * cos²θ * csc²θ

=  \dfrac{sin\theta}{cos\theta} * \dfrac{cos\theta*cos\theta}{} *\dfrac{1}{sin\theta*sin\theta}

= \dfrac{cos\theta}{sin\theta}

= cotθ

Answer: B

<u>Step-by-step explanation:</u>

The parent graph is y = x²

The new graph y = -x² + 3 should have the following:

  • reflection over the x-axis
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Answers:

  • a. Quadrant II
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  • c. \dfrac{\pi}{6}
  • d. C
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<u>Explanation:</u>

\dfrac{17\pi}{6} - \dfrac{12\pi}{6} = \dfrac{5\pi}{6}

a) Quadrant 2 is: \dfrac{\pi}{2} < \theta < \pi

b) In Quadrant 2, cos is negative and sin is positive, so tan is negative

c) \pi-\dfrac{5\pi}{6} = \dfrac{\pi}{6}

d) the reference line is above the x-axis so it is negative -->  -tan\dfrac{\pi}{6}

e) tan(\dfrac{5\pi}{6})=\dfrac{1}{-\sqrt{3}}=-\dfrac{\sqrt{3}}{3}


4 0
3 years ago
A bicycle is traveling at 22 miles per hour. How many feet will it cover in 45 seconds? Round your answer to the nearest tenth o
puteri [66]
  • Answer:

<em>1452 feet</em>

  • Step-by-step explanation:

<em>1 hour = 60min×60sec = 3600 sec</em>

<em>1 miles = 5280 feet</em>

<em>22 miles = 22×5280ft = 116160 ft</em>

<em />

<em>3600sec ................. 116160 ft</em>

<em>45sec ................................ x ft</em>

<em>x = 45×116160/3600</em>

<em>= 5227200/3600</em>

<em>= 1452 feet</em>

7 0
4 years ago
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