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evablogger [386]
2 years ago
11

-8/9 - (2 1/3) show all your work

Mathematics
1 answer:
Sauron [17]2 years ago
8 0

Answer:

1 8/9 - 1 2/3 = 2/

9

≅ 0.2222222

Step-by-step explanation:

How do you solve fractions step by step?

Conversion a mixed number 1 8/

9

to a improper fraction: 1 8/9 = 1 8/

9

= 1 · 9 + 8/

9

= 9 + 8/

9

= 17/

9

To find a new numerator:

a) Multiply the whole number 1 by the denominator 9. Whole number 1 equally 1 * 9/

9

= 9/

9

b) Add the answer from previous step 9 to the numerator 8. New numerator is 9 + 8 = 17

c) Write a previous answer (new numerator 17) over the denominator 9.

One and eight ninths is seventeen ninths

Conversion a mixed number 1 2/

3

to a improper fraction: 1 2/3 = 1 2/

3

= 1 · 3 + 2/

3

= 3 + 2/

3

= 5/

3

To find a new numerator:

a) Multiply the whole number 1 by the denominator 3. Whole number 1 equally 1 * 3/

3

= 3/

3

b) Add the answer from previous step 3 to the numerator 2. New numerator is 3 + 2 = 5

c) Write a previous answer (new numerator 5) over the denominator 3.

One and two thirds is five thirds

Subtract: 17/

9

- 5/

3

= 17/

9

- 5 · 3/

3 · 3

= 17/

9

- 15/

9

= 17 - 15/

9

= 2/

9

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(9, 3) = 9. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 9 × 3 = 27. In the following intermediate step, it cannot further simplify the fraction result by canceling.

In other words - seventeen ninths minus five thirds = two ninths

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Answer:

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 and  

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Step-by-step explanation:

Let

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equate the equations and solve for n

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Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

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We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

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Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

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Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

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