Question

I wanna know how to get this answer using the quadratic formula 4t2 + 9t − 3 = 0

Answer 1

$\text{The quadratic formula is:}\\\\x=\frac{-b\pm\sqrt(b^2-4ac)}{2a}\\\\\text{In the equation, your 4 is a, 9 is b, and -3 is c}\\\\\text{Plug in and solve:}\\\\t=\frac{-9\pm\sqrt(9^2-4(4)(-3))}{2(4)}\\\\t=\frac{-9\pm\sqrt(81-4(4)(-3))}{2(4)}\\\\t=\frac{-9\pm\sqrt(81+48)}{2(4)}\\\\t=\frac{-9\pm\sqrt129}{2(4)}\\\\t=\frac{-9\pm\sqrt129}{8}\\\\\text{Since you can't simplify any further, that'll be your answer}\\\\\boxed{t=\frac{-9+\sqrt129}{8}\,\,and\,\,t=\frac{-9-\sqrt129}{8}}$