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Sunny_sXe [5.5K]
3 years ago
11

I wanna know how to get this answer using the quadratic formula 4t2 + 9t − 3 = 0

Mathematics
1 answer:
motikmotik3 years ago
6 0

\text{The quadratic formula is:}\\\\x=\frac{-b\pm\sqrt(b^2-4ac)}{2a}\\\\\text{In the equation, your 4 is a, 9 is b, and -3 is c}\\\\\text{Plug in and solve:}\\\\t=\frac{-9\pm\sqrt(9^2-4(4)(-3))}{2(4)}\\\\t=\frac{-9\pm\sqrt(81-4(4)(-3))}{2(4)}\\\\t=\frac{-9\pm\sqrt(81+48)}{2(4)}\\\\t=\frac{-9\pm\sqrt129}{2(4)}\\\\t=\frac{-9\pm\sqrt129}{8}\\\\\text{Since you can't simplify any further, that'll be your answer}\\\\\boxed{t=\frac{-9+\sqrt129}{8}\,\,and\,\,t=\frac{-9-\sqrt129}{8}}

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if you look at the part where the first part connects with the second part:

y = 5 if x < - 2

y = -2x + 1 if  -2 ≤ x < 1

we don't have a discontinuity there, so there shouldn't be a dot.

<h3></h3><h3>What is wrong with the graph?</h3>

When we graph over intervals like (a, b) or [a, b] or something like that, we use dots to define the end of the intervals, and to denote that the function ends abruptly or we have a jump.

In this case, you can see that between the end and the second part and the beginning of the third part there is a jump, so the use of dots is correct there, but if you look at the part where the first part connects with the second part:

y = 5 if x < - 2

y = -2x + 1 if  -2 ≤ x < 1

we don't have a discontinuity there, so there shouldn't be a dot.

That is the only error with the graph.

If you want to learn more about piecewise functions:

brainly.com/question/3628123

#SPJ1

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