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Varvara68 [4.7K]
3 years ago
13

Ben rolls two standard number cubes 36 time. predict how many time he will roll a sum of four.

Mathematics
1 answer:
rusak2 [61]3 years ago
6 0
You can make a 6 x 6 square to illustrate  the probabilities 

   1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 *
5 6 7 8 9  * &
6 7 8 9  * & $

* =10, & =11, $ = 12, I wanted maintain spacing

There are 3 4's. So it is 3/36 chance, which is 1/12 chance.
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Find the lengths of the missing side . Simplify all radicals !!!<br> help mee!!!!!!
larisa86 [58]

Answer:

e = 13\sqrt{2}

f = 13\sqrt{2}

Step-by-step explanation:

The ∆ given is an isosceles ∆ with a right angle measuring 90°, and two congruent angles measuring 45° each.

Using trigonometric ratio formula, we can find the lengths of the missing side as shown below:

Finding e:

sin(\theta) = \frac{opp}{hyp}

sin(\theta) = sin(45) = \frac{\sqrt{2}}{2}

hyp = 26

opp = e = ?

Plug in the values into the formula

\frac{\sqrt{2}}{2} = \frac{e}{26}

Multiply both sides by 26

\frac{\sqrt{2}}{2}*26 = \frac{e}{26}*26

\frac{\sqrt{2}}{2}*26 = e

\frac{\sqrt{2}}{1}*13 = e

13\sqrt{2} = e

e = 13\sqrt{2}

Since side e is of the same length with side f, therefore, the length of side f = 13\sqrt{2}

3 0
3 years ago
Which expression is equivalent to 15a^8b^4/5a^4b?<br> 3a^2b^4<br> 3a^4b^3<br> 10a^4b^3<br> 10a^4b^4
EleoNora [17]

Answer:

3 a^12 b^5

Step-by-step explanation:

Simplify the following:

(15 a^8 b^4 a^4 b)/5

15/5 = (5×3)/5 = 3:

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3 a^8 b^4 a^4 b = 3 a^(8 + 4) b^(4 + 1):

3 a^(8 + 4) b^(4 + 1)

4 + 1 = 5:

3 a^(8 + 4) b^5

8 + 4 = 12:

Answer: 3 a^12 b^5

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3 years ago
An executive committee consists of 15 members: 7 men &amp; 8 women. 5 members are selected at random to attend a meeting in Hawa
asambeis [7]

Answer:

1.8%

Step-by-step explanation:

(8c5 * 7c0)/15c5

= 0.018

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this is a shorthand way of writing very large or very small numbers in which the number is expressed as a number between 1 and 1
Flauer [41]

Answer:

function

Step-by-step explanation:

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3 years ago
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