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Alika [10]
2 years ago
6

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam

e-day ticket
is $70. For one performance, 15 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1500. What was
the price of each kind of ticket?
Advance ticket: s
?
Mathematics
1 answer:
skad [1K]2 years ago
5 0

Answer:

The advanced tickets cost $25 an the same-day ticket cost $30

Step-by-step explanation:

You might be interested in
What is the length of side c, given a = 10, b = 8, and c = 105°?
posledela
We can calculate using cosinus method in triangle
c² = a² + b² - 2ab cos c

Plug in the number to the formula
c² = a² + b² - 2ab cos c
c² = 10² + 8² - 2(10)(8) cos 105°
c² = 100 + 64 - 160 cos 105°
c² = 164 - 160 (-0.26)
c² = 164 + 41.6
c² = 205.6
c = √205.6
c =14.34

C is 14.34 unit length
5 0
3 years ago
Please help i always give brainliets and thanks
pav-90 [236]

Answer:

(3)

Step-by-step explanation:

(1), (2) and (4)

can be written as Fr= p1-p2, F and r are inversely proportional

(3) r is directly proportional with F which is opposite to the given formula

hence this is incorrect

6 0
3 years ago
The wading pool shown is a trapezoidal prism with a total volume of 286 cubic feet. What is the missing dimension? First base: 8
harkovskaia [24]
To find the missing dimension you will use the formula for finding the volume of a prism and solve for the missing dimension.  In this case 2ft is how deep the pool is and you will solve for the width of the pool.

V = Bh, where B is the area of the base.  In this case, use the area of a trapezoid formula.

286 = 1/2h(8 +13)2
<u>286</u> = <u>21h</u>
21      21
h = 13.6

The width of the wading pool is approximately 13.6 feet.
5 0
3 years ago
PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!In two or more complete sentences explain how you would set up and solve the following eq
olchik [2.2K]

Peter's account is 910-40x, and Marla's account is 470-2x. This is a system, so you must find the number that makes both equations end up with the same number. Basically trial and error. Here is what I did:

Let's try the number 10. 910-400=510 and 470-20=450. I need a higher number.

Let's try 13 next. 910-520=390 and 470-26=444. Now the number has to be lower.

Let's try 12. 910-480=430 and 470-24=446. Close, and a little lower.

11.5 is too low, and 11.7 is too high.  11.6 has Equation 1 at 446 and Equation 2 at 446.8. Very close!

It is somewhere around 11.6. I hope that this can give you a start in figuring it out, because I don't believe in giving the complete answer, because then you do not learn anything from it.

4 0
3 years ago
Read 2 more answers
The ratio of boys to girls in a group is 7:1. If there are 66 more boys than girls, work out how many girls there are
nevsk [136]

Answer:11

Step-by-step explanation:

Boys : girls=7:1

Sum of ratio=7+1=8

Let them number of girls be y

Then they number of boys=y+66

Total number of pupils=y+y+66

Total number of pupils=2y+66

Number of girls=(girls ratio)/(sum of ratio) x (total number of pupils)

y=1/8 x (2y+66)

Cross multiply

y x 8=2y + 66

8y=2y + 66

Collect like terms

8y-2y=66

6y=66

Divide both sides by 6

6y/6=66/6

y=11

The number of girls is 11

4 0
3 years ago
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