A presidential candidate plans to begin her campaign by visiting the capitals in 44 of 4343 states. what is the probability that
she selects the route of fourfour specific capitals? is it practical to list all of the different possible routes in order to select the one that is best?
If the 4 states have to be in a specific order say ABCD,
then the total number of different possible routes is:
43P4 = 2,961,840
So the probability is:
1 / 2,961,840 = 3.38 x 10^-7
But if the 4 states can be in any order such as DBAC,
ACBD etc, then the total number of different possible routes is:
43C4 = 123,410
So the probability is:
1 / 123,410 = 8.1 x 10^-6
No I don’t think it is practical to list all the
different possible routes to select the one that is best. We can simply use
mathematical models to solve for that one.
When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.
If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.
Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so
.
Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so
.
Subtract from the first equation the second equation: