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Wittaler [7]
3 years ago
15

A presidential candidate plans to begin her campaign by visiting the capitals in 44 of 4343 states. what is the probability that

she selects the route of fourfour specific​ capitals? is it practical to list all of the different possible routes in order to select the one that is​ best?
Mathematics
1 answer:
QveST [7]3 years ago
4 0

If the 4 states have to be in a specific order say ABCD, then the total number of different possible routes is:

 43P4 = 2,961,840

So the probability is:

1 / 2,961,840 = 3.38 x 10^-7

 

But if the 4 states can be in any order such as DBAC, ACBD etc, then the total number of different possible routes is:

 43C4 = 123,410

So the probability is:

1 / 123,410 = 8.1 x 10^-6

 

No I don’t think it is practical to list all the different possible routes to select the one that is best. We can simply use mathematical models to solve for that one.

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t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5    

The degrees of freedom are given by:

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Step-by-step explanation:

Information provided

\bar X=3.3 represent the sample mean in ppm

s=0.4 represent the sample standard deviation

n=9 sample size  

\mu_o =2.3 represent the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value

System of hypothesis

We want to verify if the true mean is higher than 2,3 ppm, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.3  

Alternative hypothesis:\mu > 2.3  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5    

The degrees of freedom are given by:

df=n-1=9-1=8  

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Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

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brainliest?

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