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Roman55 [17]
3 years ago
11

Carla has a dog walking service and makes $9 for every day works walking dogs. One week, she was sick and could only walk the do

gs on 2 days. The following week, she felt better, so she worked 4 days. How much money did she make? What is the equation? Show the solution.
Mathematics
1 answer:
Alexeev081 [22]3 years ago
5 0

Answer: 18+36=$54

Step-by-step explanation: The first week that she was sick, she walked dogs 2 times, meaning she would earn $18 (2*9=18).

The second week when she walked dogs 4 times, she'd earn $36 (4*9=36).

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-18=2+5x solve for x
Korvikt [17]

Answer:

x=-4

Step-by-step explanation:

-18=2+5x

Subtract 2 from both sides

-20=5x

-4=x

3 0
2 years ago
Read 2 more answers
Can someone please help me answer this question. I dont know what to do.
pogonyaev

Answer:

7

Step-by-step explanation:

hi , you can see here we have a rectangle without a triangle :

area rectangle - area  triangle = area of the shape

Area of the triangle= L x l

=4 x 2

=8

Area of the triangle = \frac{b X h}{2}

=\frac{2 X 1}{2}

=1

So we do :   8 - 1 = 7

I hope it is gonna be helpful,

have a nice day.

3 0
3 years ago
The side lenghts of a square measures 10x+5. the side lenghts of a triangle are 30x,3x and 6x+30. the square and triangle have t
Goshia [24]
(10x+5)4 = 30x + 3x + 6x +30

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perimeter of the square= 420
perimeter of the triangle= 420
5 0
2 years ago
3.1a+3.2=<br> \,\,10.33<br> 10.33
alexgriva [62]

Answer:

hi

Step-by-step explanation:

7 0
2 years ago
Question 2 please fas
Len [333]

Answer:

a = 3, b = 2

Step-by-step explanation:

It is given that both the polynomials are equal.

Therefore, h(x) = k(x)

{x}^{3}  + (a + b) {x}^{2}  - 4x + 2 \\  =  {x}^{3}  + 5 {x}^{2}  - (2a - b)x + 2 \\  \\ equating \: like \: terms \: on \: both \: sides \\ (a + b) {x}^{2}  = 5 {x}^{2}   \\  \implies \: a + b = 5.....(1) \\  \\  - (2a - b)x =  - 4x \\ 2a - b = 4....(2) \\  \\ adding \: equations \: (1) \: and \: (2) \\  \\ 3a = 9 \\   \implies \: a =  \frac{9}{3}  \\   \huge \red{ \boxed{\implies \: a = 3}} \\  \\ substituting \: a = 3 \: in \: equation \: (1) \\ 3 + b = 5 \\   \implies \: b = 5 - 3 \\ \huge \purple{ \boxed{ \implies  b = 2}}

5 0
3 years ago
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