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vlada-n [284]
3 years ago
5

Solve this one pleeaasssee

Mathematics
1 answer:
Tamiku [17]3 years ago
4 0

Answer:

the answer is c

Step-by-step explanation:

when looking at the graph you can see the intersection point which is (4,3) and at 4 months they were both 3 pounds. at the point of intersection they were the same age and same weight.

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Simplify.<br><br> [3 • (3 – 9)] + 9
Marat540 [252]

Answer:

(9-27)+9

=-18+9

<em><u>=-9</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em>

4 0
3 years ago
PLEASE HELP ME FAST!!!!
poizon [28]
The answer is going to be A
3 0
3 years ago
PLEASSEEEEEEEE HELLPPPPPPPP MEEEEEEEE
Jet001 [13]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please someone help me solve this i dpnt know the answer​
kozerog [31]
<h2><u>Answer With Explanation:</u></h2>

<u>Firstly, let's start with <XOZ: =55°</u>

We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)

<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>

These 2 angles are joined to create an equilateral triangle which always adds up to 180°

So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°

<u>Thirdly, <QON: =55°</u>

This angle lies on the line XON which needs to add up to 180°

As we worked out before, <XOZ was 55°

So, <ZOQ was already given as 70°

We then do 55+70=125 then 180-125=55°

<QON is 55°

(I'm only in Grade 9 LOL)

4 0
2 years ago
The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow
Reika [66]
If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now    \bf \begin{cases}&#10;A=l\cdot w\\\\\&#10;A=3000000\\&#10;----------\\&#10;3000000=l\cdot w\\\\&#10;\frac{3000000}{w}=l&#10;\end{cases}\qquad thus&#10;\\\\\\&#10;P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}&#10;\\\\\\&#10;P=3w+6000000w^{-1}\\\\&#10;-----------------------------\\\\&#10;now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}&#10;\\\\\\&#10;\textit{so the critical points are at }&#10;\begin{cases}&#10;0=w^2\\\\&#10;0=\frac{3w^2-6000000}{w^2}&#10;\end{cases}

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the 0=w^2\implies 0=w   so.  you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0
3 years ago
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