(3*6)*9= 162. 3*(6*9)=162
WHAT WAS THE ANSWER I HAVE THAT TEST RN
Answer:
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = 0.4404
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 0.10 inches
Given that the standard deviation of the population = 0.07inches
Let 'X' be a random variable in a normal distribution
![Z = \frac{x-mean}{S.D} = \frac{0.11-0.10}{0.07} = 0.1428](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7Bx-mean%7D%7BS.D%7D%20%3D%20%5Cfrac%7B0.11-0.10%7D%7B0.07%7D%20%3D%200.1428)
<u><em>Step(ii):-</em></u>
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = P(Z≤0.1428)
= 1-P(Z≥0.1428)
= 1 - ( 0.5 +A(0.1428)
= 0.5 - A(0.1428)
= 0.5 -0.0596
= 0.4404
<u><em>Final answer:-</em></u>
The probability that the mean daily precipitation will be 0.11 inches or less for a random sample of November days
P(X≤ 0.11) = 0.4404
II(RS is a median) and III(RS is a side of RST)
To find the
![x_i](https://tex.z-dn.net/?f=x_i)
intercept, set
![x_j=x_k=0](https://tex.z-dn.net/?f=x_j%3Dx_k%3D0)
. By this I refer to the following procedure.
x-intercept: Set
![y=z=0](https://tex.z-dn.net/?f=y%3Dz%3D0)
, then you're left with
![4x=60\iff x=15](https://tex.z-dn.net/?f=4x%3D60%5Ciff%20x%3D15)
. Then the x-intercept is
![(15,0,0)](https://tex.z-dn.net/?f=%2815%2C0%2C0%29)
.
y-intercept: Set
![x=z=0](https://tex.z-dn.net/?f=x%3Dz%3D0)
, then
![-6y=60\iff y=-10](https://tex.z-dn.net/?f=-6y%3D60%5Ciff%20y%3D-10)
. The y-intercept is
![(0,-10,0)](https://tex.z-dn.net/?f=%280%2C-10%2C0%29)
.
z-intercept: Set
![x=y=0](https://tex.z-dn.net/?f=x%3Dy%3D0)
, then
![-5z=60\iff z=-12](https://tex.z-dn.net/?f=-5z%3D60%5Ciff%20z%3D-12)
. The z-intercept is
![(0,0,-12)](https://tex.z-dn.net/?f=%280%2C0%2C-12%29)
.