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Yuliya22 [10]
3 years ago
15

Find the area enclosed by the curve y^2=x^2-x^4

Mathematics
1 answer:
yulyashka [42]3 years ago
4 0

Answer: 4/3

Step-by-step explanation:

As you know this graph is a lemniscate

4\int\limits^1_0 {x\sqrt{1-x^{2} } \, dx =\frac{4}{3} =1.33$

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Jenna made money babysitting, and she also earned $20 cleaning her neighbor's basement. During the week, her total earnings were
Firlakuza [10]

Answer:

Jenna spent 7 hours babysitting.

Step-by-step explanation:

With the information provided, you can say that Jenna's total earnings are equal to the amount she earned cleaning her neighbor's basement plus the result of multiplying the charge per hour for babysitting for the number f hours, which is:

e=20+5x, where:

e represents the total earnings

x is the number of hours

Now, you can replace e with 55 that is the toal amount she earned and solve for x:

55=20+5x

55-20=5x

35=5x

x=35/5

x=7

According to this, the answer is that Jenna spent 7 hours babysitting.

7 0
3 years ago
Daniel and Audrey are reading the same book. At the beginning of the month, Daniel was on page 49 and Audrey was on page 22. Dan
dolphi86 [110]

Answer:

202

Step-by-step explanation:

So it has to end in 2 because 20t+22 will always be a 2.

day1:

17x1+49=66

no 2

day2:

17x2+49=83

odd

day3:

D=100

no 2

day4:

odd

day5:

D=134

no 2

etc

keep adding 17 to D until you get one that ends in 2

D=202

A=202

6 0
3 years ago
Simplify -6 + [4 - (x-2) ]<br><br> A. x<br> B. –x<br> C. 1 – x<br> D. –4 – x
Dominik [7]
The answer is B
-6+[4-(x-2)]
-6+4-x+2
-x
6 0
3 years ago
1) What's the standard form of<br> a quadratic function?
PSYCHO15rus [73]

Answer:

Standard Form - Y=ax^2+bx+c

Vertex - Y=a(x-h)^2+k

Step-by-step explanation:

7 0
4 years ago
The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d
EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2}).

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})

                   =P(Z>1)\\\\=1-P(Z

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0
3 years ago
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