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3 years ago

Find the area enclosed by the curve y^2=x^2-x^4

Mathematics

1 answer:

yulyashka [42]3 years ago

4 0

Answer: 4/3

Step-by-step explanation:

As you know this graph is a lemniscate

$4\int\limits^1_0 {x\sqrt{1-x^{2} } \, dx =\frac{4}{3} =1.33$$

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Step-by-step explanation:

$x = \frac{30}{7}$

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Graph each equation y=7x-7<br><img src="https://tex.z-dn.net/?f=y%20%3D%207x%20-%207" id="TexFormula1" title="y = 7x - 7" alt="y

Dafna1 [17]

to graph a LINEar equation, since it's just a straight line, recall, to draw a straight line all you need is two points.

so we can just pick two random "x" values, hmmmmm say x = 0, what's "y"?

y = 7(0)-7 => y = -7....................................... so that gives us the point (0, -7)

hmmm x = 2, what is "y"?

y = 7(2) - 7 => y = 14-7 => y = 7................. so we get the point (2, 7).

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e-lub [12.9K]

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Relation 1 and 2 are not functions

Step-by-step explanation:

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Plz please help❤️ With only 5 please

Rufina [12.5K]

Answer:

4. -1/2 and 2

5. N and R

Step-by-step explanation:

Well if you want me too do 5 I’ll do 4 too.

So for #4 it’s actually pretty simple we just have to seperate y that’s it.

So first we have to get y by itself by subtracting 3x to the other side so the equation looks like this now $6y=-3x+12$ .

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So we have to graph y = -1/2x + 2 so look at the image below.

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