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3 years ago

Choose the single logarithmic expression that is equivalent to the one shown.

2 answers:

8 0

log 24. The formula for logarithmic addition is log (a) + log (b) = log(ab). Substituting 8 and 3 for a and b respectively gives the result log 24.

Oksanka [162]3 years ago

3 0

The first thing you should know is that there are properties for logarithms.
One of them is the following one:
Let a and b be numbers, by property of logarithms:
log (a * b) = log (a) + log (b)
Therefore, by applying the property shown we have:
log 8 + log 3 = log (8 * 3)
log 8 + log 3 = log (24)
the answer is
log 24

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The prior probabilities for events A1 and A2 are P(A1) = 0.30 and P(A2) = 0.55. It is also known that P(A1 ∩ A2) = 0. Suppose P(

k0ka [10]

We're given the following probabilities:

$P(A_1)=0.30$

$P(A_2)=0.55$

$P(A_1\cap A_2)=0$

$P(B\mid A_1)=0.20$

$P(B\mid A_2)=0.05$

(a) Yes, $A_1$ and $A_2$ are mutually exclusive. This is exactly what zero probability of their intersection means. The two events cannot occur simultaneously.

(b) Use the definition of conditional probability to expand:

$P(A_1\cap B)=P(A_1)P(B\mid A_1)=0.30\cdot0.20=0.06$

$P(A_2\cap B)=P(A_2)P(B\mid A_2)=0.55\cdot0.05=0.0275$

$P(B)=P(A_1\cap B)+P(A_2\cap B)=0.06+0.0275=0.0875$

(d) Bayes' theorem says

$P(A_1\mid B)=\dfrac{P(A_1)P(B\mid A_1)}{P(B)}=\dfrac{0.30\cdot0.20}{0.0875}\approx0.686$

$P(A_2\mid B)=\dfrac{P(A_2)P(B\mid A_2)}{P(B)}=\dfrac{0.55\cdot0.05}{0.0875}\approx0.314$

3 0

3 years ago

Answer this question for points or brainliest

aleksklad [387]

Answer:

I'll have both

Step-by-step explanation:

so anyway I started blasting

5 0

2 years ago

27÷819= give me the quotient for 27÷819

Dafna11 [192]

Answer:

0.03296703

Step-by-step explanation: Just put this in the calculator and it will give you an answer. If youb dont have a calculator then look it up on the computer!

~Cake Queen (:

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3 years ago

What is the perimeter of this composite figure? 4 cm 6 cm

AlekseyPX

4cm I think, because it’s usually a even and equal number. But don’t take my word for it.

8 0

1 year ago

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You are in charge of purchases at the student-run used-book supply program at your college, and you must decide how many introdu

mariarad [96]

Answer:

Calculus texts: 600
History texts: 0
Marketing texts: 0

Step-by-step explanation:

Each Calculus text returns $10/2 = $5 per unit of shelf space. For History and Marketing texts, the respective numbers are $4/1 = $4 per unit, and $8/4 = $2 per unit. Using 1200 units of shelf space for 600 Calculus texts returns ...

$5/unit × 1200 units = $6000 . . . profit

Any other use of units of shelf space will reduce profit.

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3 years ago