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sergiy2304 [10]

3 years ago

8

A silo in the shape of a cylinder is partially filled with corn to cows. The corn fills 50% of the height of the silo. What is t

he approximate volume of the part of the silo that is filled with corn if the silo is 12ft in diameter and 60ft high?

1 answer:

kondaur [170]3 years ago

5 0

The volume of the part of silo filled with corn is 3391.2 cubic foot.

Step-by-step explanation:

Diameter of the silo = 12ft.

Radius = 6 ft.

Height = 60ft.

Volume = π(r x r) h

= (3.14) (36) 60

= 6782.4 cubic foot

The corn is 50% filled. So,

Volume of corn filled = (50/100) (6782.4)

= 3391.2 cubic foot

The volume of the part of silo filled with corn is 3391.2 cubic foot.

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Answer and explanation:

Given : The position of an object moving along an x axis is given by $x=3.24t-4.20t^2+1.07t^3$ where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(1)=3.24(1)-4.20(1)^2+1.07(1)^3$

$x(1)=3.24-4.20+1.07$

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b) At t= 2 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(2)=3.24(2)-4.20(2)^2+1.07(2)^3$

$x(2)=6.48-16.8+8.56$

$x(2)=-1.76$

c) At t= 3 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(3)=3.24(3)-4.20(3)^2+1.07(3)^3$

$x(3)=9.72-37.8+28.89$

$x(3)=0.81$

d) At t= 4 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(4)=3.24(4)-4.20(4)^2+1.07(4)^3$

$x(4)=12.96-67.2+68.48$

$x(4)=14.24$

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

$\triangle x=x(4)-x(0)$

$\triangle x=14.24-0$

$\triangle x=14.24$

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity is given by,

$\triangle x=x(4)-x(2)$

$\triangle x=14.24-(-1.76)$

$\triangle x=14.24+1.76$

$\triangle x=16$

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3 years ago