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Aleks [24]
3 years ago
12

Give the degree of each polynomial

Mathematics
2 answers:
Norma-Jean [14]3 years ago
8 0

Answer

Sorry! number 12 is 2

Step-by-step explanation:

lora16 [44]3 years ago
3 0

Answer:

Step-by-step explanation:

The highest power of the variable will be the degree of the polynomial.

11 )  Degree of polynomial = 3

12 ) Degree of polynomial = 2

13)Degree of polynomial = 4

14) Degree of polynomial = 5

15)Degree of polynomial = 3

16) Degree of polynomial = 5

17)Degree of polynomial = 7

18)Degree of polynomial = 4

19)Degree of polynomial =3

20)Degree of polynomial = 7

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Write the equation of a line that is parallel to the line 2x - 3y = 5 and passes through the point (2, -1)
jek_recluse [69]

Answer:

The equation of the line is 2x - 3y = 7 ⇒ answer A

Step-by-step explanation:

* Lets revise the relation between the parallel lines

- If two lines are equal then their slopes are equal

- We can make an equation of a line by using its slope and

 a point on the line

- If the slope of the line is m and passing through the point (x1 , y1),

 then we can use this form [y - y1]/[x - x1] = m to find the equation

* Lets solve the problem

- The line is parallel to the line 2x - 3y = 5

∴ the slope of the line = the slope of the line 2x - 3y = 5

- Rearrange the terms of the equation to be in the form

  y = mx + c to find the slope of it

∵ 2x - 3y = 5 ⇒ subtract 2x from both sides

∴ -3y = 5 - 2x ⇒ divide two sides by -3

∴ y = 5/-3 - 2x/-3 ⇒ y = 2/3 x - 5/3

∴ The slop of the line is 2/3

∵ The line passes through point (2 , -1)

* Lets use the rule to find the equation of the line

∵ y - (-1)/x - 2 = 2/3

∴ y + 1/x - 2 = 2/3 ⇒ by using cross multiplication

∴ 3(y + 1) = 2(x - 2) ⇒ open the brackets

∴ 3y + 3 = 2x - 4 ⇒ put x an d y in one side

∴ 2x - 3y = 3 + 4

∴ 2x - 3y = 7

* The equation of the line is 2x - 3y = 7

8 0
3 years ago
3 groups of 5 how<br> Many are there in total
Vadim26 [7]

It's 15 because

3 groups and 5 people in each group

and becomes 15

I HOPE THIS HELPS

7 0
3 years ago
Please help me with this homework
Agata [3.3K]

Answer:

-14.2, -7.8, 12.6, 15.3

Step-by-step explanation:

7 0
3 years ago
Let f be the function given by f(x)=2x^3−4x^2−5. What is the value of f′(−1) ?
Cerrena [4.2K]

f'(x) = 6x^2-8x

f'(-1) = 6(-1)^2 -8(-1)

      = 6 +8

      = 14

7 0
2 years ago
Read 2 more answers
Find a, b , and h so that f(x)= a sin (b(x-h))<br> f(x)=5cosx+2sinx
TiliK225 [7]
a\sin(b(x-h))=a\sin(bx)\cos(bh)-a\cos(bx)\sin(bh)

For this to be equivalent to 5\cos x+2\sin x, you require b=1 and

\begin{cases}a\cos h=2\\-a\sin h=5\end{cases}

Dividing the second equation by the first gives

\dfrac{-a\sin h}{a\cos h}=-\tan h=\dfrac52\implies h=\arctan\left(-\dfrac52\right)=-\arctan\dfrac52

Meanwhile, you also get

a\cos\left(-\arctan\dfrac52\right)=2\implies a\cos\left(\arctan\dfrac52\right)=\dfrac{2a}{\sqrt{29}}=2\implies a=\sqrt{29}

So,

f(x)=5\cos x+2\sin x=\sqrt{29}\sin\left(x+\arctan\dfrac52\right)
8 0
3 years ago
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