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olasank [31]
3 years ago
13

I need help please???

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

X > 6

→ 6X < 66

→ 6 x 7 < 66

→ 42 < 66 (Correct)

X > 11

→ 6X < 66

→ 6 x 12 < 66

→ 72 < 66 (Incorrect)

X = 11

→ 6X < 66

→ 6 x 11 < 66

→ 66 < 66 (Incorrect)

ANSWER:

X > 6

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students surveyed boys and girls separately to determine which sport was enjoyed the most. After completing the boys survey, it
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3 years ago
Standard form of 5y=35+10x what is the answer
ss7ja [257]

Answer: y=7+2x

Step-by-step explanation: Divide 5 by all. 5y/5=35/5 +10x/5.

4 0
3 years ago
QT 1.
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1: 3.2
2: B. 1.6
3: C. 6.4
4: D. 17.92

I'm unable to see the table for 5, are you able to attach it?
5 0
3 years ago
a. 0.98 – 0.053 b. 0.67 – 0.4 c. 0.3 – 0.002 d. 3.2 – .789 e. 6.53 – 4.298 f. 6 – 4.32 g. 7 – 3.574 h. 4.83 – 1.8 i. 3.7 – 1.8 j
Pavlova-9 [17]

a. 0.927

We have:

0.98 – 0.053

We can re-write it as:

0. 9 8 0 -

0. 0 5 3

Moving digits to the right:

0. 9 7 10 -

0. 0 5 3

Digit-per-digit subtraction:

0. 9 2 7


b. 0.27

We have:

0.67 – 0.4

We can re-write it as:

0. 6 7 -

0. 4 0

Digit-per-digit subtraction:

0. 2 7


c. 0.298

We have:

0.3 – 0.002

We can re-write it as:

0. 3 0 0 -

0. 0 0 2

Moving digits to the right:

0. 2 10 0 -

0. 0 0 2

Again:

0. 2 9 10 -

0. 0 0 2

Digit-per-digit subtraction:

0. 2 9 8


d. 2.411

We have:

3.2 – .789

We can re-write it as:

3. 2 0 0 -

0. 7 8 9

We need to rewrite the first term by moving digits to the right several times:

3. 2 0 0 = 2. 12 0 0 = 2. 11 10 0 = 2. 11 9 10

So now we have:

2. 11 9 10 -

0. 7 8 9

Digit-per-digit subtraction:

2. 4 1 1


e. 2.232

We have:

6.53 – 4.298

We can re-write it as:

6. 5 3 0 -

4. 2 9 8

We need to rewrite the first term by moving digits to the right several times:

6. 5 3 0 = 6. 5 2 10 = 6. 4 12 10

So now we have:

6. 4 12 10 -

4. 2 9 8

Digit-per-digit subtraction:

2. 2 3 2


f. 1.68

We have:

6 – 4.32

We can re-write it as:

6. 0 0 -

4. 3 2

We need to rewrite the first term by moving digits to the right several times:

6. 0 0 = 5. 10 0 = 5. 9 10

So now we have:

5. 9 10 -

4. 3 2

Digit-per-digit subtraction:

1. 6 8


g. 4.426

We have:

7 – 3.574

We can re-write it as:

7. 0 0 0 -

3. 5 7 4

We need to rewrite the first term by moving digits to the right several times:

7. 0 0 0 = 6. 10 0 0 = 6. 9 10 0 = 6. 9 9 10

So now we have:

6. 9 9 10 -

3. 5 7 4 =

Digit-per-digit subtraction:

3. 4 2 6


h. 3.03

We have:

4.83 – 1.8

We can re-write it as:

4. 8 3 -

1. 8 0

We can immediately do the digit-per-digit subtraction:

3. 0 3


i. 2.9

We have:

3.7 – 1.8

We can re-write it as:

3. 7 -

1. 8

We need to rewrite the first term by moving digits to the right:

3. 7 = 2. 17

So now we have:

2. 17 -

1. 8 =

Digit-per-digit subtraction:

2. 9


j. 4.538

We have:

16.17 – 11.632

We can re-write it as:

1 6 . 1 7 0 -

1 1 . 6 3 2

We need to rewrite the first term by moving digits to the right:

1 6. 1 7 0 = 1 6. 1 6 10 = 1 5. 11 6 10  

So now we have:

1 5. 11 6 10 -

1 1. 6 3 2 =

Digit-per-digit subtraction:

0 4. 5 3 8

3 0
3 years ago
A chocolate bar measures 30 mm wide, 70 mm long, and (or 4.5) mm high. Will's Wrapping Company is making a wrapper to cover the
KiRa [710]

Hey there! I'm happy to help!

First, let's find the area of the top of the bar.

30×70=2100

This is the same as the bottom of the bar, so we have another 2100 mm, giving us 4200 in total.

Now we want to find the two long sides. This is 70×4.5, which is 315. Since there are two of these sides, we have another 315, giving us 630 in total there.

Now we have the short sides.

30×4.5=135

135×2=270

Now, we add up all of these measurements.

4200+630+270=5100

Therefore, Will's Wrapping Company will need 5100 mm² of paper to make their wrapper.

Have a wonderful day! :D

8 0
3 years ago
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