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Verdich [7]
3 years ago
12

Consider equation of circle x2-2x+y2-4y-4=0,if line 2x-y+a=0 is its diameter then find value of a

Mathematics
1 answer:
g100num [7]3 years ago
4 0

Answer:

Step-by-step explanation:

x² - 2x + y² - 4y - 4 = 0

x² - 2x + y² - 4y = 4

complete the squares

(x² - 2x + x₀) + (y² - 4y + y₀) = 4

the unknown number will be the square of half of the x¹ coefficient

(x² - 2x + 1) + (y² - 4y + 4) = 4 + 1 + 4

(x - 1)² + (y - 2)² = 9

This tells us that the circle is centered on (1, 2)

Which is also a point on the diameter

2x - y + a = 0

a = y - 2x

a = 2 - 2(1)

a = 0

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3 years ago
Select all the expressions that are equivalent to -36x+54y−90.
CaHeK987 [17]

Answer:

b) -18(2x -3y + 5)

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Step-by-step explanation:

a) -9( 4x - 6y - 10) = -36x + 54y + 90 not equal

b) -18(2x - 3y + 5) = -36x + 54y - 90 equal

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7 0
3 years ago
Read 2 more answers
Which could be the first step in solving this system of equations by substitution?
Ainat [17]

Answer:

The first step is to replace the y in y-x=15 with 7x (we can do this because the first equation tells us that they're equal)

solve and get

(2.5,17.5)

or x= 2.5 y=17.5

Step-by-step explanation:

The first step is to recognize that y=7x which means that we can just replace the y in the second equation with 7x

7x-x=15

6x=15

x=2.5

Then we can solve for y

y=7(2.5)

y=17.5

3 0
3 years ago
Question in picture
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8 0
3 years ago
2/3(3/5x+9)=1/2(2x+40)<br><br> I posted this before but w/o the 1/2 on accident
andriy [413]
The answer and working are shown in the photo below
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2 years ago
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