Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:

item i:
Velocity is the <u>derivative of the position</u>, hence:

Item ii:

The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:

Item iv:

The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:




Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer:
1. -19x
3. 23 - 8x
5. -18x + 2y
Step-by-step explanation:
first: 3x - x = 2x
2x - 22x = -20x
-20x + x = -19x
second one:
8 - (-15) = 23
12x - 20x = -8 x
23 - 8x
third:
-10x - 8x = -18x
3y - y = 2y
-18x + 2y
Answer:

Step-by-step explanation:

Using rule of exponents 

Using rule of exponents 


To equalize the negative sign, we'll move t to the denominator

Answer: A
Step-by-step explanation:
If you flip the second triangle straight upwards so that x is on top and z,y are on the bottom, you could visualize the points and angles in the same locations.