Okay the way to do this: Find the probability of the first event and then the probability of the second event. Then, multiply the probabilities. So:
(7/13)*(6/12)
So the answer is about .27 or 27%
Given:
The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.
To find:
The expected enrollment in 2010.
Solution:
Percentage decrease formula:
The percentage decrease in between 1950 and 1960 is:
The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.
The expected enrollment in 2010 is:
Therefore, the expected enrollment in 2010 is 7.875 thousands.
You'd say that although that seems correct, since there's a 50/50 chance of each outcome, it doesn't necessarily guarantee that it will ALWAYS be 50/50. However, her guess has the highest probability of occurring, or in other words, its more likely that it'll be somewhere close to 240 rather than in the 100's or 300's.
Answer:
-4
Step-by-step explanation:
8-5= 3
x/3= 4
12/3=4
-16+12=-4
Square 33 is the first square in Row 5, the first square of the second half of the chessboard. How many pennies are on square 33?
Answer : 2^32
