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love history [14]

3 years ago

13

Which is greater 4/28 or 4/42. Explain

1 answer:

sergij07 [2.7K]3 years ago

3 0

Answer:The answer is 4/28 is greater.

Step-by-step explanation:

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What is the answer?please

alexdok [17]

The answer is a^2-64

6 0

2 years ago

What is the answer?

Pani-rosa [81]

The answer should be D

Number more than 3: 4, 5 and 6

Frequency of each number greater than three:
4- 20
5-30
6-38

Add them you get 88

Total frequency: 200

Therefore: 88/200 = 0.44

5 0

2 years ago

A necklace has and matching bracelet have two types of beads. The necklace has 12 large beads and 8 small beads and weighs 88 gr

miv72 [106K]

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Step-by-step explanation:

Let,

Weight of one large bead = x

Weight of one small bead = y

According to given statement;

12x+8y=88 Eqn 1

5x+2y=25 Eqn 2

Multiplying Eqn 2 by 4

$4(5x+2y=25)\\20x+8y=100\ \ \ Eqn\ 3\\$

Subtracting Eqn 1 from Eqn 3

$(20x+8y)-(12x+8y)=100-88\\20x+8y-12x-8y=12\\8x=12$

Dividing both sides by 8

$\frac{8x}{8}=\frac{12}{8}\\x=1.5$

Putting x=1.5 in Eqn 1

$12(1.5)+8y=88\\18+8y=88\\8y=88-18\\8y=70$

Dividing both sides by 8

$\frac{8y}{8}=\frac{70}{8}\\y=8.75$

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

2 years ago

ryan bought a house for 120000 and his house is fina ed at a rate of 7.4% and the payoff os in 120 months . how much is his mont

sleet_krkn [62]

Answer: p=354.3

Step-by-step explanation:

3 0

2 years ago

If A, B, and C are n times nn×n invertible matrices, does the equation Upper C Superscript negative 1 Baseline (Upper A plus U

jeyben [28]

Looks like the matrix equation is supposed to be

$C^{-1}(A+X)B^{-1}=I_n$

where $I_n$ presumably denotes the $n\times n$ identity matrix.

Since $A,B,C$ are all invertible, we have by multiplying on the left by $C$ ,

$C(C^{-1}(A+X)B^{-1})=CI_n$

$(CC^{-1})((A+X)B^{-1})=C$

$(A+X)B^{-1}=C$

then multiplying on the right by $B$ ,

$((A+X)B^{-1})B=CB$

$(A+X)(B^{-1}B)=CB$

$A+X=CB$

and finally subtracting $A$ from both sides to end up with

$X=CB-A$

5 0

3 years ago