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Ghella [55]
3 years ago
6

Pls help find shaded area

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
6 0
<h3>Exact area = 12pi - 9*sqrt(3)  square inches</h3><h3>Approximate area = 22.1106545749577 square inches</h3>

==========================================================

Work Shown:

Assuming the chord is horizontal along with the diameter, then this means the two smallest minor arcs are both 30 degrees each. This leaves the northern most arc to be 180-30-30 = 120 degrees in measure

A = area of northern sector (you can think of it as a pizza slize)

A = (angle/360)*pi*r^2

A = (120/360)*pi*6^2

A = 12pi

B = area of triangle

B = (1/2)*side1*side2*sin(included angle)

B = (1/2)*6*6*sin(120)

B = 18*sqrt(3)/2

B = 9*sqrt(3)

C = area of shaded region

C = A - B

C = 12pi - 9*sqrt(3)  .... exact area

C = 22.1106545749577 ... use a calculator to get the approximate area

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Matthew scored a total of 168 points in basketball this season. He scored 147 of those in the regular season, and and the rest w
MaRussiya [10]

Answer:

12.5%

Step-by-step explanation:

Step1. Determine the points Matthew had during playoff by subtracting points made during regular season from total points in season.

   168 points this season

-   <u>147 points regular season </u>

    21 points scored in playoff

Step 2. Get the percentage, by dividing playoff points over total points in season

21 ÷ 168 = 0.125

Step 3. Multiply it by 100 to get the percentage equivalent from decimal.

0.125 x 100% = 12.5%

7 0
3 years ago
X, Y and Z form the vertices of a triangle. XY = 12.4m, XZ = 10.4m and YZ = 8.7m. Find the angle ∠ YXZ rounded to 1 DP.
sweet-ann [11.9K]

Answer:

43.8°

Step-by-step explanation:

Applying,

Cosine rule,

From the diagram attached,

x² = y²+z²-2yxcos∅.................... Equation 1

where ∅ = ∠YXZ

Given: x = 8.7 m, y = 10.4 m, z = 12.4 m

Substitute these values  into equation 1

8.7² = 10.4²+12.4²-[2×10.4×12.4cos∅]

75.69 = (108.16+153.76)-(257.92cos∅)

75.69 = 261.92-257.92cos∅

collect like terms

257.92cos∅ = 261.92-75.69

257.92cos∅ = 186.23

Divide both sides by the coefficient of cos∅

cos∅ = 186.23/257.92

cos∅ = 0.722

Find the cos⁻¹ of both side.

∅ = cos⁻¹(0.7220)

∅ = 43.78°

∅ = 43.8°

6 0
3 years ago
Write the slope intercept equation of the function f whose graph satisifies the given conditions. The graph of f passes through
MrMuchimi
  • Let's find slope first.

  • (1,-2)
  • (-8,6)

\\ \sf\longmapsto m=\dfrac{6+2}{-8-1}

\\ \sf\longmapsto m=\dfrac{8}{-9}

Slope intercept form

\\ \sf\longmapsto y=mx+b

\\ \sf\longmapsto y=-\dfrac{8}{9}x-2

3 0
3 years ago
HELP ASAP!!!<br> thanks if you helped!
Anton [14]

Answer:

G. \frac{11}{20}

Step-by-step explanation:

3 0
2 years ago
A scale model of a ramp is a right triangular prism as given in this figure. in the actual ramp, the triangular base has a heigh
kakasveta [241]

The surface area of the actual ramp including the underside is 16.8 ft²

The height of the actual ramp = 1.2 feet  

The height of the model = 6 cm

<h3>What is the surface area of a right triangular prism?</h3>

A right triangular prism is a 3-dimensional triangle with two congruent triangular faces and 3 rectangular faces that connect the triangular.

The surface area of a right triangular prism

= (Perimeter of the base × Length of the prism) + (2 × Base Area)

Scale factor = 1.2 feet / 6 cm = 0.2 ft/cm

Actual base = 16 cm × 0.2 ft/cm = 3.2 ft

convert the units

9 cm = 9 cm × 0.2 ft/cm = 1.8 ft

10 cm = 10 cm × 0.2 ft/cm = 2 ft

The surface area of a right triangular prism

= (Perimeter of the base × Length of the prism) + (2 × Base Area)

Surface area of actual ramp = 2(0.5 × 3.2 ft × 1.2 ft) + 2(2 ft × 1.8 ft) + (1.8 ft × 3.2 ft)

= 16.8 ft²

Hence, the surface area of the actual ramp including the underside is 16.8 ft²

Learn more about the area here:

brainly.com/question/25292087

3 0
3 years ago
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