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Gennadij [26K]
3 years ago
9

The point (1,-1) is on the terminal side of angle theta in standard position what are the values of sine cuisine and tangent of

theta
Mathematics
1 answer:
pickupchik [31]3 years ago
3 0
\bf \textit{terminal point }\implies 
\begin{array}{lclcll}
(&1&,&-1)\\
&\uparrow &&\uparrow \\
&x&&y
\end{array}
\\\\\\
sin(\theta)=\cfrac{y}{r}
\qquad 
% cosine
cos(\theta)=\cfrac{x}{r}
\qquad 
% tangent
tan(\theta)=\cfrac{y}{x}\\\\
-----------------------------\\\\
\textit{so, what's the radius "r"?}\implies r^2=x^2+y^2\implies r=\sqrt{x^2+y^2}
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faltersainse [42]

Answer:

a. 58

b. 35

Step-by-step explanation:

a. Given,

sinθ = cos 32

We know that cos x = sin (90 - x)

⇒ sin θ = sin (90 - 32)

⇒ sin θ = sin 58

⇒ θ = 58

Thus, the value of θ would be 58.

b. Given,

cosθ = sin(θ+20),

sin (90 - θ) = sin (θ + 20)

⇒ 90 - θ = θ + 20

⇒ 90 - 20 = θ + θ

⇒ 70 = 2θ

⇒ θ = 35

Thus, the value of θ would be 35.

8 0
3 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x = <br><br> I NEED HELP ASAP
melomori [17]

The sum of the angles of a triangle is 180°. So you can do:

91° + (8x + 3)° + (10x - 4)° = 180°   To find x, you need to isolate/get the variable "x" by itself in the equation. First combine like terms (terms that have the same variable and power/exponent]

91 + 3 - 4 + 8x + 10x = 180      (I rearranged for the like terms to be next to each other)

90 + 18x = 180      Subtract 90 on both sides

18x = 90       Divide 18 on both sides to get "x" by itself

x = 5

PROOF

91° + (8x + 3)° + (10x - 4)° = 180°       Plug in 5 for "x"

91° + (8(5) + 3)° + (10(5) - 4)° = 180°

91° + (40 + 3)° + (50 - 4)° = 180°

91° + 43° + 46° = 180°

180° = 180°

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Marta_Voda [28]

Answer:

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8 0
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On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Gala2k [10]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are given  that

f(x)=6(\frac{1}{3})^x

Function f decreases from quadrant  2 to quadrant 1 and approaches  y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

(x,y)\rightarrow (-x,y)

Using the rule then we get

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

By using

x^{-a}=\frac{1}{x^a}

Substitute x=-1

g(-1)=6\times (\frac{1}{3})=2

Substitute x=0

g(0)=6

Therefore,g(x)=6(3)^x is true.

8 0
3 years ago
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The answer to you’re question is H
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