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Gennadij [26K]
3 years ago
9

The point (1,-1) is on the terminal side of angle theta in standard position what are the values of sine cuisine and tangent of

theta
Mathematics
1 answer:
pickupchik [31]3 years ago
3 0
\bf \textit{terminal point }\implies 
\begin{array}{lclcll}
(&1&,&-1)\\
&\uparrow &&\uparrow \\
&x&&y
\end{array}
\\\\\\
sin(\theta)=\cfrac{y}{r}
\qquad 
% cosine
cos(\theta)=\cfrac{x}{r}
\qquad 
% tangent
tan(\theta)=\cfrac{y}{x}\\\\
-----------------------------\\\\
\textit{so, what's the radius "r"?}\implies r^2=x^2+y^2\implies r=\sqrt{x^2+y^2}
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<h2>C) (negative 1, one-half), (0, 1), (1, 2), (2, 4)</h2>

Step-by-step explanation:

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