The volume of the pyramid would be 2406.16 cubic cm.
<h3>How to find the volume of a square-based right pyramid?</h3>
Supposing that:
The length of the sides of the square base of the pyramid has = b units
The height of the considered square-based pyramid = h units,
The pyramid below has a square base.
h = 24.4 cm
b = 17.2 cm
Then, its volume is given by:


Therefore, the volume of the pyramid would be 2406.16 cubic cm.
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W=-5 because you distribute at the beginning with the 2 variables and you solve that's equation and you will end up with 6w divided by 30 and that's will give u W=-5
Answer:
Area of the regular dodecagon inscribed in a circle will be 27 square units.
Step-by-step explanation:
A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.
Since angle formed at the center by a polygon = 
Therefore, angle at the center of a dodecagon =
= 30°
Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units
Now area of a small triangle = 
where a and b are the sides of the triangle and θ is the angle between them.
Now area of the small triangle = 
= 
Area of dodecagon = 12×area of the small triangle
= 12×
= 27 unit²
Therefore, area of the regular octagon is 27 square unit.
Answer:
y = -2x - 7
Step-by-step explanation:
x - 2y = 6
-2y = -x + 6
Divide the whole equation by (-2)

slope = 1/2
Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/2)

(-3, - 1)
y -y1 = m(x -x1)
y - [-1] = -2(x - [-3])
y + 1 = -2(x + 3)
y + 1= x* (-2) + 3*(-2)
y + 1 = -2x - 6
y = -2x - 6 - 1
y = -2x - 7