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Gennadij [26K]
3 years ago
9

The point (1,-1) is on the terminal side of angle theta in standard position what are the values of sine cuisine and tangent of

theta
Mathematics
1 answer:
pickupchik [31]3 years ago
3 0
\bf \textit{terminal point }\implies 
\begin{array}{lclcll}
(&1&,&-1)\\
&\uparrow &&\uparrow \\
&x&&y
\end{array}
\\\\\\
sin(\theta)=\cfrac{y}{r}
\qquad 
% cosine
cos(\theta)=\cfrac{x}{r}
\qquad 
% tangent
tan(\theta)=\cfrac{y}{x}\\\\
-----------------------------\\\\
\textit{so, what's the radius "r"?}\implies r^2=x^2+y^2\implies r=\sqrt{x^2+y^2}
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Step-by-step explanation:

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A riverboat travels 54 km downstream in 2 hours. It travels 57 km upstream in 3 hours. Find the speed of the boat and the speed
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Here we must write and solve a system of equations to find the speed of the boat and the speed of the stream. We will find that the boat's speed is 23km/h and the river's speed is 4km/h.

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Now let's define the variables we will be using:

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When the boat travels downstream, the total speed of the boat is the speed of the boat plus the speed of the river, and we know that in that case it travels 54km in 2 hours, then:

54km = (B + R)*2h

When the boat travels upstream, we must subtract the speed of the river. In that case, we know that the boat travels 57km in 3 hours, then we have:

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Then our system of equations is:

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To solve this, first, we need to isolate one of the variables in one of the equations, let's isolate B in the second one:

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Now we can replace that in the other equation:

54km = (B + R)*2h

54km/2h = B + R

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Now we can solve this for R:

27 km/h = 19km/h + 2*R

27 km/h - 19km/h = 2*R

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Now that we know the value of R, we can use:

B = 19 km/h + R  = 19 km/h + 4km/h = 23 km/h

So the boat's speed is 23km/h and the river's speed is 4km/h.

If you want to learn more, you can read:

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5 0
2 years ago
Question 2: You want to donate 30% of the $400 earned at your yard sale to
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Answer:

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Step-by-step explanation:

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sorry for the bad spelling

4 0
3 years ago
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