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Law Incorporation [45]
2 years ago
6

Why would it be unethical to have a control group that wore seatbelts and a treament group that did not

Mathematics
1 answer:
koban [17]2 years ago
5 0

Answer:

Because there is a chance that one control group will get injured, or maybe even die.

Step-by-step explanation:

Putting one's life in danger is considered unethical and is well, illegal.

You might be interested in
Which equation represents the line passing through the points (3, 2) and (–9, 6)?
prisoha [69]
(3,2),(-9,6)
slope = (6 - 2) / (-9 - 3) = -4/12 = -1/3

y = mx + b
slope(m) = -1/3
use either of ur points...(3,2)....x = 3 and y = 2
now we sub into the formula and find b, the y int
2 = -1/3(3) + b
2 = -1 + b
2 + 1 = b
3 = b
so ur equation is : y = -1/3x + 3 <==
4 0
3 years ago
An executive is earning $45,000 per year. This is
Marizza181 [45]
Her salary 4 years ago would have been $30,000.

If 45,000 is 15,000 less than double her previous salary, we must first add 15,000 to 45,000 to find what double her salary was.

45,000+15,000=60,000.

Since this is twice her salary, we divide this by 2.

60,000/2= 30,000.

So, her salary 4 years ago would have been $30,000.

I hope this helps!
4 0
2 years ago
John works two jobs. He earns $10 an hour babysitting his neighbor's children and $15 an hour mowing lawns in his neighborhood.
Jlenok [28]
Add up all the numbers
7 0
2 years ago
Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
HEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPP WITH ANSWER PLZZZZ
earnstyle [38]
First, find the area of each of the prisms sides

5 by 5.5 = 27.5

3 by 5.5 = 16.5

4 by 3 cut in half = 6 (theres 2 of thoses so 12)

4 by 5.5 = 22

Add up the products and the surface area is 78 units

Post brainliest if this helped :)
4 0
3 years ago
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