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Law Incorporation [45]
3 years ago
6

Why would it be unethical to have a control group that wore seatbelts and a treament group that did not

Mathematics
1 answer:
koban [17]3 years ago
5 0

Answer:

Because there is a chance that one control group will get injured, or maybe even die.

Step-by-step explanation:

Putting one's life in danger is considered unethical and is well, illegal.

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It cost $36.75 for three tickets to visit the science center. It cost $51 for 4 tickets to visit the zoo. Which attraction will
Ber [7]
Find the cost for one ticket for the science center.
36.75 ÷ 3 = 12.25
Multiply the product with 12 to get the cost of 12 tickets.
12.25 × 12 = 147
Find the cost of 1 zoo ticket.
51 ÷ 4 = 12.75
Find the cost of 12 tickets by multiplying the product and 12
12.75 × 12 = $153
12 Science Center Tickets cost $147
12 zoo tickets cost $153

The Zoo costs more than the Science Center.

To find out how much more the Zoo costed, subtract 147 from 153.
153 - 147 = 6
The zoo only costs $6 more for 12 students.
So, you're answers are Zoo and $6
8 0
3 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
I don’t know how to do this math problem
Svetach [21]

Answer:

I'll help

Step-by-step explanation:

No worries man

3 0
3 years ago
Read 2 more answers
Solve the Quadratic Equation . Show all of your work for full credit. 4x^2− 2x − 5= 0
max2010maxim [7]
Hope this helps! Don’t mind the part I crossed off.

8 0
3 years ago
Read 2 more answers
3 over eight people ride the bus in Mrs. Mulls class. If she has 24 students how many students ride the bus?
qaws [65]
I think you divide 24 by 8 which = 3 and then times 3•3 which equals 9 so I think that 9 students out of 24 ride the bus
8 0
3 years ago
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