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kipiarov [429]
2 years ago
5

P is the set of positive integer factors of 20, and Q is the set of positive integer factors of 12. If x is a member of set P an

d y is a member of set Q what is the greatest possible value of x-y?
Mathematics
1 answer:
Leokris [45]2 years ago
8 0

Answer:

please check the attachments for better explanation

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(2^(3)*(-2)^(3)*3^(3))/(2^(3*2)*4^(4(-2))*8^(3))=?
TEA [102]

Answer:

-3456

Step-by-step explanation

7 0
3 years ago
If $-2 < x \le 3,$ then find all possible values of $5x + 1.$ Give your answer in interval notation.
kotegsom [21]

Answer: (-9, 16]

This is the interval from -9 to 16. Exclude -9 but include 16.

=====================================================

Work Shown:

The idea is to multiply all sides by 5, then add 1 to all sides

-2 < x \le 3

5(-2) < 5x \le 5(3)

-10 < 5x \le 15

-10+1 < 5x+1 \le 15+1

-9 < 5x+1 \le 16

This converts to the interval notation  (-9, 16]

note: a curved parenthesis means "do not include this value in the solution set"; while a square bracket has us include the value. So we exclude -9 and include 16.

3 0
3 years ago
3. The values for p and q represent the equilibrium point. As related to the troupe's
svp [43]

Answer: The equilibrium point represents the raising or lowering the price in response to changes in the supply or demand.

If the price of a good is above equilibrium, this means that the quantity of the good supplied exceeds the quantity of the good demanded.

If the quantity is below the equilibrium point, it will create a shortage. because the quantity supplied is less than quantity demanded.

Hope this helps!

Step-by-step explanation:

5 0
3 years ago
If x*3=64, what is the value of x?
dusya [7]

Answer:

x = 21.3 repeating. so put the - on top of the 3 if you're writing it down

4 0
4 years ago
Read 2 more answers
Given the function f(x) = x3 + 2x2 − 3x − 5, what is resulting function when f(x) is shifted to the right 1 unit?
cluponka [151]
When shifted to the right 1 unit it would be:
f(x - 1) = (x - 1)^3 + 2(x - 1)^2 - 3(x - 1) - 5 
<span>= (x^3 - 3x^2 + 3x - 1) + 2(x^2 - 2x + 1) - 3(x - 1) - 5 </span>
<span>= x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5 </span>
<span>= x^3 - x^2 - 4x - 1 
</span>I hope this helps
5 0
3 years ago
Read 2 more answers
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