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Dennis_Churaev [7]
2 years ago
9

Complete these problems to review skills of the module (Will give 70 points)

Mathematics
2 answers:
bazaltina [42]2 years ago
7 0
2. 225
3. 65
and please vote brainliest
____ [38]2 years ago
6 0
2.
1/2 (15) (13 + 17)
1/2 (15) (30)     (simplify 13 + 17)
7.5 (30)     (multiply 1/2 and 15)
225    (multiply 7.5 and 30)

3.
1/2 (10) (9.4 + 3.6)
1/2 (10) (13)      (simplify 9.4 + 3.6)
(5) (13)    (multiply 1/2 and 10)
65   (multiply 5 and 13)

Hope this helped!

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I do believe i need help.
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Answer:

A

Step-by-step explanation:

Can't have 0 in the denominator

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The last one at the right

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Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

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3 0
3 years ago
What is the slope of the line shown below ?
ElenaW [278]

Answer:

4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

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3 years ago
If f(x)=x sqrt -25 and g(x)=x-5, what is the domain of (f/g)(x)?
givi [52]

Answer:

<h2>R-{5}</h2>

Step-by-step explanation:

f(x)=x²-25=(x-5)(x+5)

g(x)=x-5

(f/g)(x)=<em>(x-5)</em>(x+5)/<em>(x-5)</em>=x+5;   for x≠5

D=R-{5}

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3 years ago
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