1)v/4-3=5
v-12=20
v=32
2)u/5+3=1
u+15=5
u=-10
3)6+z/9=9
54+z=81
z=27
4)-7+f/2=-1
-14+f=-2
f=12
5)9+w/4=-5
36+w=-20
w=-56
6)e/7-3=-5
e-21=-35
e=-14
7)-8+d/5=2
-40+d=10
d=50
8)u/5+3=6
u+15=30
u=15
9)f/-3+5=8
f-15=-24
f=-9
Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
hope it really helps......!!!!!
To solve, isolate the x. Cross multiply
3/13(13)(5) = x/5(5)(13)
3(5) = (13)x
Simplify
13x = 15
Isolate the x. Divide by 13.
13x/13 = 15/13
x = 15/13
x = 1.2
1.2 is your answer
hope this helps
Answer:
I think it's 150
Step-by-step explanation:
(8+7) × 10 = 150
