Answer: Yes
Step-by-step explanation:
Step #1: Lacey has 2 3/4 yards of wrapping paper remaining. She has six boxes to wrap, each of which requires 3/8 of a yard of paper. First, you must find the total number of yards of wrapping paper needed for six boxes.
Number of boxes * Number of wrapping paper required for each box
6 x 3/8 = 9/4
Step #2: Subtract the number of yards of wrapping paper remaining by the total number of wrapping for 6 boxes.
2 3/4 - 9/4 = 1/2
Step #3: Determine and solve whether Lacey will have enough wrapping paper left to also wrap a book that requires 1/2 yard of paper. To solve, subtract the remaining amount of wrapping paper by the amount of wrapping required for a book.
1/2 - 1/2 = 0
So, yes Lacey will have just enough wrapping paper to also wrap a book that requires 1/2 yard of paper.
(8z - 10) ÷ (-2) + 5(z - 1) is equal to "Z"
- - Final answer: Z<span />
Data,title,independent, dependent viabarles...constants
Answer:½((n/2) – ½) – ½ = 10
½(n/2) – ¼ - ½ = 10 (using the distributive property)
¼n – ¼ - ½ = 10 (multiplying to eliminate the parentheses)
¼n – ¾ = 10 (combining like terms)
¼n = 10¾ (adding ¾ to both sides of the equation)
n = 43 (dividing both sides of the equation by ¼)
Step-by-step explanation:
Let’s start by writing Josie’s first step as an expression. Dividing n by 2, then subtracting ½ from
the result would be (n/2) – ½. If we build on this expression with the information in Josie’s
second step, we get ½((n/2) – ½) – ½. Knowing the final result is 10, we can set up the equation
below, and solve for n as follows: hope this helps