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3 years ago

14

tickets to a play cost $11 each. There is also a service charge of $4 per order. Write ab equation for the relationship that giv

es the total cost y in dollars for an order of x tickets.

2 answers:

MA_775_DIABLO [31]3 years ago

5 0

Y+(11•X)+4

Hope this helped!

yuradex [85]3 years ago

3 0

(11•x)+4=y
I hope this is right

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a previous analysis of paper boxes showed that the standard deviation of their lengths is 15 millimeters. A packers wishes to fi

vladimir1956 [14]

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

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3 years ago

If the quadratic equation <br> 2 + 2 + 5 = 0 is<br> solved using the quadratic formula then.

taurus [48]

No solution.

Step-by-step explanation:

1) Simplify 2 + 2 to 4.

$4 + 5 = 0$

2) Simplify 4 + 5 to 9.

$9 = 0$

3) Since 9 = 0 is false, these is no solution.

$no \: solution$

7 0

3 years ago

Two faulty machines, M1 and M2, are repeatedly run synchronously in parallel (i.e., both machines execute one run, then both exe

leonid [27]

The event that either M1 or M2 fails has probability

$P(M_1\text{ fails or }M_2\text{ fails})=P(M_1\text{ fails})+P(M_2\text{ fails})-P(M_1\text{ and }M_2\text{ both fail})$

by the addition rule. Failure events are independent, so

$P(M_1\text{ and }M_2\text{ both fail})=P(M_1\text{ fails})P(M_2\text{ fails})$

so that

$P(M_1\text{ fails or }M_2\text{ fails})=p_1+p_2-p_1p_2$

Denote this probability by $p$ . Then $X$ follows a geometric distribution with this parameter $p$ and has density

$P(X=x)=\begin{cases}(1-p)^{x-1}p&\text{for }x\ge1\\0&\text{otherwise}\end{cases}$

The expectation is $\dfrac1p=\dfrac1{p_1+p_2-p_1p_2}$ .

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3 years ago

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia and older subjects before treatment 14

RideAnS [48]

Answer:

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given data mean of the Population = 104 minutes

Given sample size 'n' =14

Mean of the sample(x⁻) = 95.9 minutes

Given Standard deviation = 24.4 minutes

<u><em>Step(ii)</em></u>:-

99% confidence interval estimate of the mean weight time for a population is determined by

$(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} +Z_{0.01} \frac{S.D}{\sqrt{n} })$

$(95.9 - 2.576\frac{24.4}{\sqrt{14} } , 95.9+2.576\frac{24.4}{\sqrt{14} })$

On calculation , we get

(95.9 -16.79 , 95.9 +16.79)

(79.11 , 112.69)

<u><em>Conclusion:</em></u>-

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

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3 years ago

The Area of a rectangle is 27cm² and the length is 9cm,find the Breadth?

telo118 [61]

Answer:3

Step-by-step explanation:

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3 years ago