If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
Area = length x height.
16 x 8 = 128
128 divided by 6 which is 21.3
I am not sure if this is right but please try to see if you will get it correct.
I think Sam is correct cuz SQ is a bigger rectangle and for OM it is smaller and we only know the width
1300 = 1000 (1.08)^t
1.3 = (1.08)^t
log base 1.08 (1.3) = t
3.41 = t
Answer:
21 - 3 + 18 ÷ 6 = 21
7 x 9 - 3 x 4 + 10 = 61
Step-by-step explanation:
