3 years ago

A line with a slope of 6 passes through the points (8,h) and (5,

1 answer:

7 0

$\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{h})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-h}{5-8}=6\implies \cfrac{-8-h}{-3}=6 \\\\\\ -8-h=-18\implies -8+18=h\implies 10=h$

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Look at the picture.

1)|AM| = |MB| = x
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