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Zepler [3.9K]
3 years ago
11

A quantity of insulin used to regulate sugar in the bloodstream breaks down by about 5% each minute. A body-weight adjusted dose

is generally 10 units. (a) Write a function representing the amount of the dose that remains. (b) Graph the function. (c) About how much insulin remains after 10 minutes? . A)f(x) = 0.95(10)x; about 8 units.. B)f(x) = 10(0.95)x; about 8 units.. C)f(x) = 0.95(10)x; about 6 units.. D)f(x) = 10(0.95)x; about 6 units.
Mathematics
1 answer:
natima [27]3 years ago
7 0
A ) A function representing the amount of the dose that remains:
f ( x ) = 10 *  0.95^{x}
B ) Graph is in the attachment.
C ) f ( 10 ) = 10 * ( 0.95 ) ^10 = 10 * 0.5987 = 5.987 ≈ 6
Answer:
D ) f ( x ) = 10 ( 0.95 ) x; about 6 units.
Download docx
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Define table represents a group frequency discretion of the number of hours spent on the computer per week for 49 student. What
Scilla [17]

Observe the given data distribution table carefully.

The 5th class interval is given as,

14.0-17.4

The upper limit (UL) and lower limit (LL) of this interval are,

\begin{gathered} UL=17.4 \\ LL=14.0 \end{gathered}

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6 0
1 year ago
Change this into decimal step by step plz
nika2105 [10]

Answer:

2.6

Step-by-step explanation:

3/5 ---> ?/100

100/5 ---> 20

3       20         60

--  x           =   -------

5       20         100

60/100 = 6/10

6/10 as a decimal is 0.6

2 + 0.6

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<h2>Hope this helps!!</h2>
7 0
3 years ago
Find the quadratic function that fits the following data. which one function fits.
Oksana_A [137]

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

y=ax^2+bx+c

Use the data from the table:

y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c

We get the system of three equations:

\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.

Subtract these equations:

\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.

From the first equation

b=-120a

Substitute it into the second equation:

5600a+40\cdot (-120a)=70\Rightarrow 800a=70,\\ \\ a=\dfrac{7}{80},\\ \\ b=-120\cdot \dfrac{7}{80}=-\dfrac{21}{2}=-10.5

So,

2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25

The quadratic function is

y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25

4 0
3 years ago
Evaluate the expression, below, when a = 2 and b = 5. <br><br> (3 + a)² • (4 – b) + √36
stellarik [79]

Answer:

-19

Step-by-step explanation:

1) substitute a with 2 and b with 5

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3) solve the power

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4) solve the multiplication

-25 + 6

5) solve the sum

- 19

6 0
2 years ago
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