The total number of 3 digit even numbers is 450
Step-by-step explanation:
Step 1 :
We need to determine the number of 3 digit numbers which is even and the leftmost digit is not zero .
The 3 digits with left most digit not equal to zero starts from 100 and goes up to 998
If we consider only the even 3 digit numbers in this interval, this would form an arithmetic progression with the first number a = 100 and the common difference d = 2.
Step 2:
The last number l in this series is 998 .
So we have
a = 100
l = 998
d = 2
The nth term in the arithmetic progression is given by a + (n-1) d
so substituting the above values we get
100 + (n-1) 2 = 998
2n = 900 => n = 450
Step 3 :
Answer :
The total number of 3 digit even numbers is 450
Answer:
always true.
the expression will always be equal to +5 because -p+p is zero
at any given value to p, the value is constantly +5
Answer:
m = √n/3 -k
Step-by-step explanation:
√n = 3(k + m)
=> √n/3 = k + m
∴ m = √n/3 -k
Hope this helps!!
Answer:
Step-by-step explanation:
I'm going to guess that the square exponents are on the top y's only? then answer b) looks good
