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vivado [14]
3 years ago
13

Can someone help me with this?

Mathematics
1 answer:
Ann [662]3 years ago
3 0
So first you have to add all of the sides and then you have to multiply 
                          Hope it helped 
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Enter the values for the highlighted variables to
kotegsom [21]

Answer:

a= -1

b=-9

c=9

d=3

e=3

f=2

g=1.5

Step-by-step explanation:

8 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
What is the radius of a sphere if its surface area is 2,122.64 square inches? (Use 3.14 for .)
Lady_Fox [76]
\bf \textit{surface area of a sphere}\\\\
SA=4\pi r^2~~
\begin{cases}
r=radius\\
------\\
SA=2122.64
\end{cases}\implies 2122.64=4\pi r^2
\\\\\\
\cfrac{2122.64}{4\pi }=r^2\implies \cfrac{530.66}{\pi }=r^2\implies \sqrt{\cfrac{530.66}{\pi }}=r
8 0
3 years ago
Read 2 more answers
Use the elimination to solve this equation. <br><br> 2x+3y=55 <br> 9x+4y=105
seropon [69]
X=5 y=15 (5,15). 
This is how you do it:
-4(2x+3y=55): -8x-12y=-220
3(9x+4y=105):27x+12y=315

You add the two new equations together, canceling out the y values, and get the x value. Then, you go back and plug in the x value in the original equation to get the y value.

6 0
3 years ago
Can you simplify 3/r + 7/r+3
Nutka1998 [239]
Combine the fractions by finding a common denominator. 
10r+9/r(r+3)
7 0
3 years ago
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