Can someone help me with this?

Marta_Voda [28]

4(2x5 + 3) - 4(2) + 2(5).

4(13) - 18.

52-18 = 34.

4 0

3 years ago

What is the solution to the system that is created by the equation y= 2x + 10 and the graph shown below? (–8, –6) (–4, –2) (0, 2

Natasha_Volkova [10]

Answer:

The solution to the system that is created by the equation y = 2x + 10 is

( -8 , -6 )

Step-by-step explanation:

Given:

y = 2x + 10

Justification:

For a Point to be a solution of the system of the equation of a line then it must satisfy the equation by substituting the X coordinate and Y coordinate.

Left hand side = Right-hand side

For point (–8, –6)

Put x = -8 and y = -6 in the given equation then

Left hand side = y

= -6

Right-hand side = 2× -8 + 10

= -16 + 10

= -4

∴ Left hand side = Right-hand side

∴ Point (–8, –6) is the Solution for y = 2x + 10

For points (–4, –2), (0, 2), and (2, 4)

Left hand side ≠ Right-hand side

∴ Points (–4, –2), (0, 2), and (2, 4) are not a Solution.

3 0

4 years ago

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8) There are three pairs of socks of three different types A, B, and C in a drawer. The goal is to pair these socks. If socks ar

tino4ka555 [31]

Answer: 2

I'm really struggling with this concept, hoping you guys could help me out.

The pairs have been separated out and you must take out a pair of socks.

Consider these problems and provide a calculation for each:

Probability of drawing a matching pair if you randomly draw 2 socks?

Probability of drawing a matching pair if you randomly draw 3 socks?

(Repeats up to randomly drawing 5 socks)

For 2 socks I got the following:

40 possible socks * 39 other possible socks = 1560 possible combinations of socks / 2 (to remove duplicate matches) = 780

For each set of socks, there are 8. 8 * 7 (7 other socks to each being matched) = 56 possible combinations in each set of socks / 2 to remove duplicates = 28 possible combinations of socks in each set.

28 / 780 = 0.036 probability of drawing a pair when drawing 2 socks from the drawer.

Step-by-step explanation:

7 0

3 years ago

ACME Manufacturing claims that its cell phone batteries last more than 32 hours on average in a certain type of cell phone. Test

son4ous [18]

Answer:

We can conclude that the battery life is greater than the 32 hour claim.

Step-by-step explanation:

The null hypothesis is:

$H_{0} = 32$

The alternate hypotesis is:

$H_{1} > 32$

Our test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}$

In which X is the statistic, $\mu$ is the mean, $\sigma$ is the standard deviation and n is the size of the sample.

In this problem, we have that:

$X = 37.8, \mu = 32, \sigma = 10, n = 18$

So

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{37.8 - 32}{\frac{10}{\sqrt{18}}}$

$t = 2.46$

We need to find the probability of finding a mean time greater than 37.8. If it is 5% of smaller(alpha = 0.05.), we can conclude that the battery life is greater than the 32 hour claim.

Probability of finding a mean time greater than 37.8

1 subtracted by the pvalue of z = t = 2.46.

z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069 < 0.05

So we can conclude that the battery life is greater than the 32 hour claim.

5 0

3 years ago

Which ordered pair (m, n) is a solution to the given system of linear equations?

LuckyWell [14K]

Answer:

Option (c) is correct.

The ordered pair (-4, -1) is a solution to the given system of linear equations.

Step-by-step explanation:

given : system of linear equations.

6m - 5n = 14

2m + 2n = - 10

We have to find the solution to the given system of linear equations.

Consider the given system of linear equations.

6m - 5n = 14 ......(1)

2m + 2n = - 10 .......(2)

We solve the given system using elimination method,

multiply equation (2) by 3 , we have,

(2) ⇒ 6m + 6n = - 30 ..............(3)

Subtract equation (1) and (3) we have,

6m + 6n - (6m - 5n) = - 30 -14

Simplify, we have,

6n + 5n = - 44

11n = - 44

n = - 4

Put n = -4 in (1) , we have,

6m - 5n = 14 ⇒ 6m - 5(-4) = 14 ⇒ 6m = 14 -20 ⇒ 6m = -6 ⇒ m = -1

Thus, the ordered pair (-4, -1) is a solution to the given system of linear equations.

8 0

4 years ago

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