To find the probability that both balls are white you will find the probability of getting a while ball from each situation separately and then multiply these probabilities together.

1. 7/14 or 1/2 chance
2. 3/9 or 1/3 change

1/2 x 1/3 = 1/6

You will have a 1 in 6 chance of getting a white ball from both urns.

7 0

3 years ago

A sphere has a volume of Vequals=3600 in cubedin3. Find its surface area.

Mice21 [21]

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4}{3}\pi r^3\qquad 
\begin{cases}
r=radius\\
------\\
V=3600
\end{cases}\implies 3600=\cfrac{4}{3}\pi r^3
\\\\\\
3600=\cfrac{4\pi r^3}{3}\implies \sqrt[3]{\cfrac{3\cdot 3600}{4\pi }}=\boxed{r}\\\\
-----------------------------\\\\
\textit{surface area of a sphere}\\\\
S=4\pi r^2\implies S=4\pi \left(\boxed{\sqrt[3]{\cfrac{3\cdot 3600}{4\pi }}} \right)^2$

simplify away

8 0

3 years ago

PLEASE help with these 2 questions<br><br> thank you!

Sergio039 [100]

Download the app photo math help a whole lot

6 0

3 years ago

Simplify and leave in radical form. <br> 8√x^2 y^6

IrinaK [193]

Step-by-step explanation:

$\sqrt[8]{ {x}^{2} {y}^{6} } \\ \\ = ( {x}^{2} {y}^{6} )^{ \frac{1}{8} } \\ \\ = {x}^{2 \times \frac{1}{8}} {y}^{6\times \frac{1}{8}} \\ \\ = x^{\frac{1}{4}} {y}^{3\times \frac{1}{4}} \\ \\ = x^{\frac{1}{4}} {y}^{\frac{3}{4}} \\ \\ = \sqrt[4]{x {y}^{3} } \\$

4 0

3 years ago