Answer:
The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
Sample of 421 new car buyers, 75 preferred foreign cars. So 
85% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
Answer:
17/38 or ≈ 0.45
Step-by-step explanation:
(-7) -10 / (-28)-10
= -17 / -38
= 17/38
You can keep the answer in fraction as 17/38 or ≈ 0.45
Hope this help you :3
The frist line may be one with the numbers 0, 1 and 2 and 10 divisions (marks at equal distance) between each integer. Each division will be equal to 0.1 units and then you can mark the second division from the zero point to the right as the 0.20 mark.
The other line must have the same integers, 0 , 1 and 2 placed in identical form as the first line. Then
- draw an inclined straight line since the point zero,
- mark 5 points in the inclined lined equally spaced over the line.
- draw a sttraight line from the 5th point to the point with the mar 1 over the base number line.
- draw a parallel line to the previous one passing trhough the second point of the inclined line and mark the point where this parallel touchs the base number line. This point shall be at the same distance from zero than the 0.2 mark was in the first number line, meaning that 0.2 and 1/5 are equivalent.
