3 years ago

What is the area of a square with a9 cm side long

1 answer:

7 0

Okay to find this answer you have to do length times width and length is 9 so width would be 9 also to find the total you multiply 9 times 9 = 81 so 81 is the answer hope this will help. :p

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6. Solve the equation. 2x - 3 = -4x - 9 A-1 B 6 C-6 DO

Oksanka [162]

Answer:

x=-1

Step-by-step explanation:

2x - 3 = -4x - 9

Add 3 and 4x on both sides.

2x + 4x = -9+3

Add or subtract like terms.

6x = -6

Divide 6 into both sides.

6x/6=-6/6

x=-1

The solution to this equation is x=-1.

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Step-by-step explanation:

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Verizon [17]

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4 years ago

Simplify -6 + [4 - (x-2) ] A. x B. –x C. 1 – x D. –4 – x

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3 years ago

Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x^3 − 3x^2 − 9x + 4 (a) Find the interval on which

Eduardwww [97]

Answer:

(-∞, -1 )∪(3, ∞)

Step-by-step explanation:

Given function,

$f(x) = x^3 - 3x^2 - 9x + 4$

Differentiating with respect to x,

$f'(x)=3x^2-6x-9$

For increasing or decreasing,

f'(x) = 0

$\implies 3x^2-6x-9=0$

By quadratic formula,

$x=\frac{-(-6)\pm \sqrt{(-6)^2-4\times 3\times -9}}{6}$

$=\frac{ 6\pm \sqrt{36+108}}{6}$

$=\frac{6\pm \sqrt{144}}{6}$

$\frac{6\pm 12}{6}$

$\implies x = 3\text{ or } x = -1$

In interval (-∞, -1 ), f'(x) = positive,

⇒ f(x) is increasing on (-∞, -1 ),

In interval (-1, 3), f'(x) = negative,

⇒ f(x) is decreasing on (-1, 3),

In interval (3, ∞), f'(x) = positive,

⇒ f(x) is increasing on (3, ∞),

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3 years ago