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podryga [215]
4 years ago
10

NEED HELP FOR TEST LAST QUESTION: Given that (6,1) is on the graph of f(x), find the corresponding point for the function f(3x).

Mathematics
2 answers:
prisoha [69]4 years ago
6 0

Answer:

2,1

Step-by-step explanation:

6/3=2

2,1

SIZIF [17.4K]4 years ago
3 0

we are given

point (6,1) on the graph of y=f(x)

we have to find point corresponding to f(3x)

Whenever we get f(ax) , we always divide x-value by 'a' unit to get point

and we will keep y-value same

x-value is 6

so, new x-value will be 6/3=2

so, our point for f(3x) will be (2,1)........Answer

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5%

Step-by-step explanation:

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Read 2 more answers
Pls help me I’ll<br> Mark you brainlessness
KATRIN_1 [288]

Answer:

for 6 it is b and for 7 it is 75

Step-by-step explanation:

fr 6 the range is higher making it much more accurate,

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7 0
3 years ago
I want yo nkow how to simplify
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Remove parentheses by multiplying factors.
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3 years ago
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Step-by-step explanation:

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4 0
3 years ago
3. Sam and Tim each have savings accounts. Every month they each put in some of their
Setler [38]

Answer:

y = 30x +50 --- Sam

y = 20x +80 --- Tim

Step-by-step explanation:

Given

Sam                         Tim

х  --- f(x) ---------------  g(x)

1  --- 80   --------------- 100

2  --- 110  --------------- 120

3  --- 140 --------------- 140

4 --- 170 -------------- 160

Required

Determine the y value

y value implies the equation of the table

Calculating the equation of Sam

First, we need to take any corresponding values of x and y

(x_1,y_1) = (1,80)

(x_2,y_2) = (4,170)

Next, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{170 - 80}{4 - 1}

m = \frac{90}{3}

m = 30

Next, we calculate the line equation using:

y - y_1=m(x-x_1)

y - 80 = 30(x - 1)

y - 80 = 30x - 30

Make y the subject

y = 30x - 30 + 80

y = 30x +50

Calculating the equation of Tim

First, we need to take any corresponding values of x and y

(x_1,y_1) = (1,100)

(x_2,y_2) = (4,160)

Next, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{160 - 100}{4 - 1}

m = \frac{60}{3}

m = 20

Next, we calculate the line equation using:

y - y_1=m(x-x_1)

y - 100 = 20(x - 1)

y - 100 = 20x - 20

Make y the subject

y = 20x - 20+100

y = 20x +80

7 0
3 years ago
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