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belka [17]
3 years ago
15

Becky adds 3/4 gallon of gasoline into her snow thrower's empty fuel tank. She uses 1/4 gallon for the snowstorm on Friday, and

then uses another 1/4 gallon for the snowstorms on Sunday. Is the fuel tank empty after becky uses the snow thrower on Sunday? Explain. If her fuel tank is not empty again, what single action could have been changed so that it is empty again? Explain.
Mathematics
1 answer:
Kaylis [27]3 years ago
8 0
Amount of fuel in the tank before the story begins . . . . . zero.

Total amount poured in . . . . . 3/4 gallon.

Total amount burned:
                   on Friday . . . . . 1/4 gallon
                   on Sunday . . . . 1/4 gallon
                        Total used . . 1/2 gallon .

Amount remaining in the tank on Monday:

               (3/4 gallon in) - (1/2 gallon burned)  =  1/4 gallon left.
                                                                        ==>  NOT empty

The tank would have been empty on Monday IF Becky
had poured in only 1/2 gallon, instead of 3/4 of a gallon
before the first flakes began to fly.
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The zero product property is best applied to factorable quadratic equations in this case.

Another factorable equation would be 2x^{2}+6x=0 since we can factor out 2x and end up with 2x(x+3)=0. Now we'll end up with two factors, 2x and (x+3), which we can apply the zero product property to.

The rest of the options are not factorable thus the zero product property won't apply to them.
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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

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