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Alborosie
3 years ago
6

Best answer will be BRAINLIEST!!!!!!

Mathematics
1 answer:
vekshin13 years ago
3 0

Answer:

252

Step-by-step explanation:

The number of integers from 100 to 999 is 999 - 100 +1 = 900.

Consider the number of three-digit integers that <em>do not contain 4 </em>as a digit.

For the <em>hundreds</em> digit, there are 8 possible choices (excluding 0 and 4).

For the <em>tens digit</em>, there are 9 possible choices (excluding 4).

For the <em>ones</em> <em>digit,</em> there are 9 possible choices (excluding 4)

Thus, there are 8 × 9 × 9 = 648 three-digit integers without a 4.

The number of three-digit integers with at least one 4 is 900 - 648 = 252.

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Can you please help me with this problem!!
Black_prince [1.1K]

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Step-by-step explanation:

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3 years ago
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Help please! <br> This question needs a bit of a hand.
worty [1.4K]

Answer:

It's not a right angle.

Step-by-step explanation:

Remark

There's a second restriction on the problem. The Perimeter is 22 cm.

AB = 8

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When you add these up, you get 8 + 5 + 9.4 which is 22.4

You may think this is close enough. In this case it is not. Either the perimeter has to 22.4 or the hypotenuse has to be reduced. Let us say it is close, but not close enough.

When you use other methods, you find out that the right angle is actually 90.4 degrees

6 0
3 years ago
Which equation is equivalent?
GarryVolchara [31]

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Step-by-step explanation:

8 0
3 years ago
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A store sells black ink pens for $5 and red ink pens for $4. John wishes to buy 20 pens but doesn’t wish to spend more than $92.
Zina [86]

Answer:  4r + 5(20-r) \le 92

=======================================

Explanation:

r = number of red pens

4r = cost of buying r red pens

example: if r = 10, then 4r = 4*10 = 40 is the total cost of buying 10 red pens

If John buys r red pens, then he must buy 20-r black pens so that r and 20-r add to 20.

John buys 20-r black pens, and at $5 each, so it will cost 5(20-r) dollars for just the black pens alone.

In total, John spends 4r + 5(20-r) dollars for all the pens (red & black)

We want $92 be the most he spends. This is the ceiling or highest value possible.

Therefore,

4r + 5(20-r) \le 92

--------------------

Extra info:

If you want to solve for r, then

4r + 5(20-r) \le 92

4r + 5(20)+5(-r) \le 92 distribute

4r + 100 - 5r \le 92  

100 - r \le 92

100-r+r \le 92+r add r to both sides

100 \le 92+r

100-92 \le 92+r-92 subtract 92 from both sides

8 \le r

r \ge 8

So John must buy at least 8 red pens. The most he can buy is 20 red pens since he wants 20 pens total.

8 0
3 years ago
Can someone please help marking brainliest
Sergio039 [100]

Answer:

down below!

Step-by-step explanation:

a) width: 2,3,4,5  length:9,8,7,6

all you need if for those numbers to add up to 11 together because the perimeter itself is 22 so you always want to be able to add those two numbers and be able to double it to the perimeter if that makes sense.

b) the greatest area there will be would be width: 5 and length: 6 because 5x6 equals 30 and multiplying the others would be less than that. hence 2x9=18, 3x8=24, and 4x7=28  

please let me know if this helps if not I can try to explain another way!

8 0
3 years ago
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