Answer:
sry I can't understand how to do this question
60
2 and 30
30
2 and 15
15
3 and 5
96
8 and 12
circle for 8 is 2 and the square is 4
circle for 12 is 2 and the last circle is also 2
Answer: option a.
Step-by-step explanation:
By definition, we know that:

Substitute
into the first equation, solve for the cosine and simplify. Then, you obtain:

As
then
:

Now we can find
:

Answer:
Resulting figure after plotting the given coordinates (0, 2) (4, 6) (10, 12) (18, 20) is a LINE.
Step-by-step explanation:
Please find the attached document for figure plotted.
Hmmm A millimeter would be too big for that .
I think millionths of a meter would be about right. Micrometers.