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Snowcat [4.5K]
3 years ago
7

X^2-x-42 what is the fractored forms

Mathematics
1 answer:
igomit [66]3 years ago
5 0
The factored forms of that is (x + 6) (x - 7).

If you have any questions then please leave a comment. Good luck!
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william is reading a book that is 50 pages long he has read 35 pages what percent of the book has he read
erik [133]
The correct answer is 70%
4 0
3 years ago
Read 2 more answers
10. Write an equation of your own that has no solution. Transform the equation to demonstrate that it has no solution
wolverine [178]
4(x+5)+6=2(2x+3)
4x+20+6=4x+6
4x+26=4x+6
Get letters on left...so subtract 4x from right and do same to left
26=6 
no solution because 26 does not equal 6
4 0
3 years ago
Read 2 more answers
assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
Given: Angle 2 is 65 degrees. What is the angle measurement of Angle 4. Explain the angle relationship used and show your work.
lesya [120]

Answer:

\angle 4 = 115^{\circ}

\angle 3 = 65^{\circ}

\angle 7 = 65^{\circ}

Step-by-step explanation:

Given

\angle 2 = 65^{\circ}

See attachment

Solving (a): \angle 4

To solve for \angle 4, we make use of:

\angle 2 +\angle 4 = 180^{\circ}

The relationship between both angles is that they are complementary angles

Make \angle 4 the subject

\angle 4 = 180^{\circ} - \angle 2

Substitute 65^{\circ} for \angle 2

\angle 4 = 180^{\circ} - 65^{\circ}

\angle 4 = 115^{\circ}

Solving (b): \angle 3

To solve for \angle 3, we make use of:

\angle 3 =\angle 2

The relationship between both angles is that they are complementary angles

\angle 3 = 65^{\circ}

Solving (c): \angle 7

To solve for \angle 7, we make use of:

\angle 7 = \angle 3

The relationship between both angles is that they are alternate exterior angles.

So:

\angle 7 = 65^{\circ}

7 0
2 years ago
Does anyone need help with simple Pythagorean theorem questions?
iren2701 [21]

Answer:

Yes

Step-by-step explanation:

Will you help me please

4 0
3 years ago
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