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Gemiola [76]
3 years ago
15

A sweater is on sale for 20% off the original price, x.

Mathematics
1 answer:
sergey [27]3 years ago
7 0
 a decrease of 20% means u r paying 80%.......so a decrease of 20% is the same as multiplying by 80%
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Which equation could be solved using the graph above?
Oduvanchick [21]

Answer:

Option b is the correct answer

Step-by-step explanation:

The graph in the picture is the graph of a quadratic equation and it takes the shape of a parabola.

The points on the x axis through which the parabola cuts across is used to determine the solution of the quadratic equation.

Looking at the parabola formed from the plotted points, it cuts the x axis at

x = -1 and x= -2

These are the factors of the equation. To get the equation, we multiply the factors.

x= -1, x +1 = 0

x =-2 , x + 2= 0

The equation is (x+1)(x+2)

Expanding the brackets,

x×x + x×2 +1×x + 1×2

= x^2 + 2x + x +2

= x^2 + 3x +2 = 0

Option b is the correct answer

6 0
3 years ago
Find the missing length.
Mandarinka [93]
The answer is 6 because 14+6=20

Hope this helps
4 0
3 years ago
Need help quick Picture provided proof problem
Doss [256]
Uhhh i dont know bsjsiw
7 0
3 years ago
Given the circle below secant kjI and tangent hi find the length of hi round to the nearest tenth if necessary.
garik1379 [7]

The length of the segment HI in the figure is 32.9

<h3>How to determine the length HI?</h3>

To do this, we make use of the following secant-tangent equation:

HI² = KI * JI

From the figure, we have:

KI = 21 + 24 = 45

JI = 24

So, we have:

HI² = 45 * 24

Evaluate the product

HI² = 1080

Take the square root of both sides

HI = 32.9

Hence, the length of the segment HI is 32.9

Read more about secant and tangent lines at:

brainly.com/question/14962681

#SPJ1

3 0
2 years ago
Given f(x) = 17-x^2, what is the average rate of change in f(x) over the interval [1, 5]
pentagon [3]
Average rate of change  over [1,5]   = f(5) - f(1)  /  5 - 1

=  [(17-5^2) - (17-1) ] / 4

=  (-8 - 16)  /  4  = -24 / 4  = -6 Answer
3 0
3 years ago
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