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3 years ago

A particle has two down quarks and one up quark. What is the charge of that particle?

Physics

2 answers:

yKpoI14uk [10]3 years ago

6 0

Answer:

The charge of the particle is 0.

Explanation:

A quark is an elementary particle of matter. Quarks combine to form Hadrons.

Quarks have fractional charges.

Up, charm and top quark has $+\frac{2}{3}$ charge.

Down, strange and bottom has $-\frac{1}{3}$ charge.

A particle which has two down quarks and one up quark will have net charge:

$2 \times (-\frac{1}{3})+1(+\frac{2}{3}) = 0$

Thus, the charge of the particle would be 0. It would be a neutral particle.

Neutron is composed of two down quarks and one up quark. It is a neutral particle.

andreev551 [17]3 years ago

3 0

The particle would be a neutron so a neutral charge. You can say the charge is 0.

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Answer:

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Explanation:

Given,

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3 years ago

Suppose that you have a 680 Ω, a 720 Ω and a 1.20 kΩ resistor. (a) What is the maximum resistance you can obtain by combining th

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Explanation:

As the given data is as follows.

$R_{1} = 680 \ohm$ ohm $\ohm$ , $R_{2} = 720 \ohm$ ohm,

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(a) We will calculate the maximum resistance by combining the given resistances as follows.

Max. Resistance = $R_{1} + R_{2} + R_{3}$

= $(680 + 720 + 1200) \ohm$ ohm

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or, = 2.6 $k\ohm$ ohm

Therefore, the maximum resistance you can obtain by combining these is 2.6 $k\ohm$ ohm.

(b) Now, the minimum resistance is calculated as follows.

Min. Resistance = $\frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}$

= $\frac{1}{680} + \frac{1}{720} + \frac{1}{1200}$

= $3.683 \times 10^{-3}$ ohm

Hence, we can conclude that minimum resistance you can obtain by combining these is $3.683 \times 10^{-3}$ ohm.

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3 years ago

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