Answer:
It needs attractive force from the strong nuclear interaction to counter the electrostatic repulsion between the protons.
Explanation:
It has to counter
Answer:
The angular velocity of the wheel in terms of d, F, and I is, ω = d/t (F/I α) s⁻¹
Explanation:
Given,
The angular velocity ω
The displacement d
The magnitude of the applied force, F
The moment of inertia of the wheel I = mr²
The angular velocity can be written as
ω = v /r
where,
v - linear velocity
r - radius of the wheel
ω = d/t (1/r) (∵ v = d /t)
The force can be written as,
F = m a
= m α r (∵ a = α r)
Multiplying both sides by r
F r = m r² α
F r = I α (∵ I = mr²)
r = I α / F
Substituting in the above equation for ω
ω = d/t (F/I α) s⁻¹
Hence, the angular velocity of the wheel in terms of d, F, and I is, ω = d/t (F/I α) s⁻¹
A cable might experience crosstalk, where the electrical signal bleeds from one wire pair to another, creating interference.
Interference is the process in which two or more waves such as light, sound or electromagnetic waves of the same frequency combine to reinforce or cancel each other, the amplitude of the resulting wave being equal to the sum of the amplitudes of the combining waves.
<span>1.0x10^3 newtons of force
1.0x10^2 kilograms of weight (assuming local gravity of 9.8 m/s^2)
I will assume that the external pressure is 1 atmosphere (101325 Pascals) since it wasn't specified in the problem. So let's simply multiply the area of the suction cup by the pressure and see what we get:
101325 P * 0.01 m^2
= 101325 kg/(m*s^2) * 0.01 m^2
= 1013.25 kg*m/s^2
= 1013.25 N
So the suction cup can support 1013.25 Newtons of force. Assuming the local gravitational acceleration is 9.8 m/s^2, let's see how many kilograms that is
1013.25 N / 9.8 m/s^2
= 1013.25 kg*m/s^2 / 9.8 m/s^2
= 103.3928571 kg
Rounding to 2 significant figures gives 1.0x10^3 newtons, or 1.0x10^2 kilograms.</span>
