Ask question

Ask question

All categories

Murljashka [212]

4 years ago

6

What does the SLOPE of a Velocity-Time graph represent? * 1 point

1 answer:

lyudmila [28]4 years ago

6 0

Acceleration

Explanation:

In the Velocity-Time graph Velocity is taken in Y-Axis and plotted against Time in X-Axis.
The unit of velocity is mentioned in m/s and unit of time is mentioned in seconds.
Here we can analyze the instantaneous acceleration and displacement covered.
From the slope we can get the body accelerated.
From the area under the graph we can get the displacement traveled.
We can calculate both average and Instantaneous acceleration from the slope of this graph.

You might be interested in

Alexander hamilton urged congress to pass a protective tariff to encourage the growth of

dezoksy [38]

To encourage the growth of manufacturing

8 0

4 years ago

The new sweet potato plant grew from the root of the original through

noname [10]

The old sweet potatoes rootlings

3 0

4 years ago

John runs 120 meters in 10 seconds and then runs back to where he started in another 10 seconds. Which statement is true? Rememb

atroni [7]

Answer:

B

Explanation:

<em>A. His speed is 0 m/s </em>

<em>B. His velocity is 12 m/s </em>

<em>C. His velocity is 0 m/s </em>

<em>D. His acceleration is 12 m/s</em>

Total distance traveled by John = 120 + 120 = 240 meters

Total time taken by John to cover the distance = 10 + 10 = 20 s

<em>Average speed of John = total distance traveled/total time taken</em>

= 240/20 = 12 m/s

Hence, the average speed/velocity of John throughout the journey is 12 m/s.

The correct option is B.

4 0

3 years ago

How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?

Aleonysh [2.5K]

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

Initial Velocity of car = 44km / hr.
Final Velocity of car = 0km / hr.
Acceleration = -5km/hr².

To Find :

Time taken to stop the car .

So , here use first equⁿ of motion which is ,

$\boxed{\red{\bf\dag v = u + at }}$

where ,

v is final Velocity.
u is Initial velocity.
a is acceleration.
t is time taken.

Now , substituting the respective values ,

$\tt:\implies v=u+at$

$\tt:\implies 0 = 44 + (-5)t$

$\tt:\implies -44 = -5t$

$\tt:\implies t=\dfrac{44}{5}$

$\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}$

$\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}$

6 0

3 years ago

Many counties in Florida missed many school days in the fall of 2004 due to hurricanes that year. A solution for how to make up

Ivenika [448]

Answer:

108 extended days

Explanation:

Regular school hours a day = 6 hr

No. of school days to make up by extending the regular hours = 3 days

Amount of time added to the regular hours of school = 10 min

No. of extended school days to make up the 3 school days by following the above mentioned criteria be x.

Time of school hours in 3 days = $3\times 6= 18\,hr\,\,\,\, ;or\,\,\, (18\times 60)\,minutes$

$\therefore x=\frac{18\times 60}{10}$

$x=108\,\,days$ are required to make up 3 days of school having 6 hours of regular timing with 10 minutes of add-on time each day.

4 0

4 years ago