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3 years ago

What does the SLOPE of a Velocity-Time graph represent? * 1 point

Physics

1 answer:

lyudmila [28]3 years ago

6 0

Acceleration

Explanation:

In the Velocity-Time graph Velocity is taken in Y-Axis and plotted against Time in X-Axis.
The unit of velocity is mentioned in m/s and unit of time is mentioned in seconds.
Here we can analyze the instantaneous acceleration and displacement covered.
From the slope we can get the body accelerated.
From the area under the graph we can get the displacement traveled.
We can calculate both average and Instantaneous acceleration from the slope of this graph.

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If you need 40.0 Nm of torque in order to loosen a nut on a wn

KonstantinChe [14]

Answer:

0.301 m

Explanation:

Torque = Force × Radius

τ = Fr

40.0 Nm = 133 N × r

r = 0.301 m

The mechanic must apply the force 0.301 m from the nut.

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3 years ago

Why does sound travel slower at a cold temperature?

tatyana61 [14]

<h2>Answer:</h2><h2>It is due to a refractment of light.</h2>

Sound moves faster in warmer air than colder air the way bends away from the warm air and back towards of air.

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3 years ago

Read 2 more answers

If we increase the distance traveled when doing work, and keep all other factors the same, what will happen?

stepladder [879]

Answer: D

Explanation:

A -amount of work

F-force

s-distance

If you keep same Force(F) and increase distance(s), amount of work will increase, according to:

A=F*s

8 0

3 years ago

Earth's neighboring galaxy, the Andromeda Galaxy, is a distance of 2.54×107 light-years from Earth. If the lifetime of a human i

Varvara68 [4.7K]

Answer:

$0.0018833\ \text{m/s}$

Explanation:

$d$ = Distance of Andromeda Galaxy from Earth = $2.54\times 10^7\ \text{ly}$

$t$ = Time taken = $90\ \text{years}$

$c$ = Speed of light = $3\times 10^8\ \text{m/s}$

We have the relation

$t=t_o\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow 90=2.54\times 10^7\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow \dfrac{90^2}{(2.54\times 10^7)^2}=1-\dfrac{v^2}{c^2}\\\Rightarrow 1-\dfrac{90^2}{(2.54\times 10^7)^2}=\dfrac{v^2}{c^2}\\\Rightarrow v=c\sqrt{1-\dfrac{90^2}{(2.54\times 10^7)^2}}$

$c-v=c(1-\sqrt{1-\dfrac{90^2}{(2.54\times 10^7)^2}})\\\Rightarrow c-v=3\times 10^8(1-\sqrt{1-\dfrac{90^2}{(2.54\times 10^7)^2}})\\\Rightarrow c-v=0.0018833\ \text{m/s}$

The required answer is $0.0018833\ \text{m/s}$ .

7 0

2 years ago

A ball is thrown straight upward and returns to the thrower's hand after 2.65 s in the air. A second ball is thrown at an angle

Leto [7]

Explanation:

I wish I could help but I am taking Biology this year!Sorry but um....check your Physics book! Also,thanks for the math help!First, find the vertical speed of ball.

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3 years ago