Complete Question
A toroidal solenoid has 590 turns, cross-sectional area 6.20 cm^2 , and mean radius 5.00 cm .
Part A. Calculate the coil's self-inductance.
Part B. If the current decreases uniformly from 5.00 A to 2.00 A in 3.00 ms, calculate the self-induced emf in the coil.
Part C. The current is directed from terminal a of the coil to terminal b. Is the direction of the induced emf from a to b or from b to a?
Answer:
Part A
Part B
Part C
From terminal a to terminal b
Explanation:
From the question we are told that
The number of turns is
The cross-sectional area is
The radius is
Generally the coils self -inductance is mathematically represented as
Where is the permeability of free space with value
substituting values
Considering the Part B
Initial current is
Current at time t is
The time taken is
The self-induced emf is mathematically evaluated as
=>
substituting values
The direction of the induced emf is from a to b because according to Lenz's law the induced emf moves in the same direction as the current
If it makes 50 complete back-and-forth wiggles in 1 second, then its frequency is <em>50 Hz</em>.
Do the data support or refute the hypothesis, normally, the data for the first part of the experiment support the first hypothesis.
<h3>What is a hypothesis test?</h3>
Hypothesis testing refers to the formal procedures used by statisticians to accept or reject these hypotheses. When trying to make decisions, it is convenient to formulate assumptions or conjectures about the populations of interest, which consist of considerations about their parameters.
As a result of this, we can see that from the complete text, there is a set of data which is used to show the force that is applied to a cart that causes the acceleration of the cart to increase which supports Newton's second law.
See more about hypothesis at brainly.com/question/4768231
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Answer:
Refractive index = 1.15
Explanation:
As we know for constructive interference of reflected light the path difference of two reflected light rays must be integral multiple of the wavelength
so here we have
now here we know that
now we have