The complete question gives the following options:
A) The 7-inch side and the 10-inch side must make a 52° angle.
B) The 7-inch side and the 10-inch side must make the 38° angle.
C) It does not matter whether or not the 7-inch side and the 10-inch side make a 52° angle.
<span> D) It does not matter whether or not the 7-inch side and the 10-inch side make the 38° angle.
According to the SAS rule for triangle congruency, two triangles are congruent if they have congruent two sides and the angle included.
Therefore, the only way to build a triangle congruent to ABC is to say that the given angle is the one included between the two sides.
Therefore, the correct answer is: </span><span>B) The 7-inch side and the 10-inch side must make the 38° angle. </span>
Answer:
Step-by-step explanation:
Begin
If this is a rhombus then <8 = 90 degrees as do all the central angles. That's because the diagonals intersect at right angles.
<4 = 38 z formation for parallel lines.
<7 = 52 The angles are part of a right angle triangle. <7 +38 = 90
<2 = 52 z formation of parallel lines (a rhombus has ll lines).
<3 = 38 The diagonals of a rhombus bisect each other.
<5 = 38 z formation for parallel lines.
<6 = 52 The diagonals of a rhombus are angle bisectors.
<1 = 52 The diagonals of a rhombus are angle bisectors.
While I'd be very glad to help you reasonably, I don't find your posting 10 questions at once to be reasonable.
Here's ONE of the problems: -2m^2 + 5mn
This can be factored, as follows: m(-2m + 5n) (answer)
Answer:
15.3 miles.
Step-by-step explanation:
Area of trapezoid is given by = 1/2*( sum of parallel side) height
Given area of trapezoid = 221.85 sq. miles
Length of parallel sides = 19 miles and 10 miles.
Sum of parallel sides = 19 miles + 10 miles = 29 miles.
Plugging the above values in formula for area of trapezoid we have
Area of trapezoid is given by = 1/2*( sum of parallel sides) height
221.85 = 1/2 (29) height
=> 221.85* 2 = 29* height
=> 443.7 = 29* height
=> 443.7/29 = height
=> height = 15.3
Thus, height is 15.3 miles.