I'll solve for y
xy+(4(20))>x-5y(2+9-7)
xy+4(20)>x-5y(2+9-7)
xy+4(20)>x-5y(4)
xy+4(20)>x-20y
xy+80>x-20y
xy+20y+80>x
y(x+20)>-80+x
y>(-80+x)/(x+20)
Step-by-step explanation:
The answer is 108. Because you multiply 3 by 9. which is 27 then you multiply 27 by 4 because thats how many 3zs there are.