Given:
Cost to build a bookshelf = $20
Cost to build a table = $45
Amount available to spend = $600
Let x = number of bookshelves built.
Let y = number of tables built.
The total number of bookshelves and tables = 18.
Therefore
x + y = 18.
That is,
y = 18 - x (1)
The total amount available to build x bookshelves and y tables = $600. Therefore
20x + 45y = 600
That is (dividing through by 5),
4x + 9y = 120 (2)
Substitute (1) into (2).
4x + 9(18 - x) = 120
4x + 162 - 9x = 120
-5x = -42
x = 8.4
From (1),obtain
y = 18 - 8.4 = 9.6
Because we cannot have fractional bookshelves and tables, we shall test values of x=8, 9 and y=9,10 for profit
Note: The profit is $60 per bookshelf and $100 per table.
If x = 8, then y = 18-8 = 10.
The profit = 8*60 + 10*100 = $1480
If x = 9, then y = 18-9 = 9.
The profit = 9*60 + 9*100 = $1440
The choice of 8 bookshelves and 10 tables is more profitable.
Answer: 8 bookshelves and 10 tables.
Answer:
I think #2
Step-by-step explanation:
Answer:
it is 512
Step-by-step explanation:
Each cow eats 12 pounds then 24 will eat 288 pounds so to know how many days it will last we will divide 10656 by 288 which is 37
so it will last for 37 days.
Answer:
d = 7, 3
Step-by-step explanation:
First, you need to isolate the absolute value
-3|d - 5| = -6
divide both sides by -3:
|d - 5| = 2
break into 2 equations:
d - 5 = 2, d - 5 = -2
solve both equations and collect solutions:
d = 5 + 2, d = 5 - 2
d = 7, 3