Answer:
a) 0.03
b) 0.68
c) 0.32
Step-by-step explanation:
We are given the following in the question:
B: companies in the area of biotechnology
I: companies in the area of information technology
P(B) = 0.2
P(I) = 0.15
The two events are given to be independent.
a) P(both companies become profitable)

0.03 is the probability that both companies become profitable
b) P(neither company becomes profitable)

0.68 is the probability that neither company becomes profitable.
c) P(at least one of the two companies become profitable)

0.32 is the probability that at least one of the two companies become profitable
A=6,500×(1+0.07÷360)^(360×5)
A=9,223.63
Interest earned
9223.63-6500==2,723.63
Answer:
The answer is 13/3.
Step-by-step explanation:
8 2/3 is an improper fraction and is expressed as 26/3. CCF (copy, change, flip) is then applied to the division statement and 26/3 to becomes 4/8*26/3. The final answer is 104/24 which simples to 13/3.
I’ll answer your question just help me with mine pls7:7
Answer:
- <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>
Explanation:
<u>Rewrite the table and the choices for better understanding:</u>
<em>Enrollment at a Technical School </em>
Year (x) First Year f(x) Second Year s(x)
2009 785 756
2010 740 785
2011 690 710
2012 732 732
2013 781 755
Which of the following statements is true based on the data in the table?
- The solution to f(x) = s(x) is x = 2012.
- The solution to f(x) = s(x) is x = 732.
- The solution to f(x) = s(x) is x = 2011.
- The solution to f(x) = s(x) is x = 710.
<h2>Solution</h2>
The question requires to find which of the options represents the solution to f(x) = s(x).
That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.
The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>
Thus, the correct choice is the third one:
- The solution to f(x) = s(x) is x = 2012.